Given a list, rotate the list to the right by k places, where k is non-negative.
For example:
Given 1->2->3->4->5->NULL
and k = 2
,
return 4->5->1->2->3->NULL
.
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode *rotateRight(ListNode *head, int k)
{
if(head==NULL || k==0) return head;
//n
ListNode *p=head;
int n=0;
while(p!=NULL)
{
n++;
p=p->next;
}
k=k%n;
if(k==0) return head;
ListNode* p1=head;
ListNode* p2=head;
for(int i=0;i<k;i++) p2=p2->next;
while(p2->next!=NULL)
{
p2=p2->next;
p1=p1->next;
}
p2->next=head;
head=p1->next;
p1->next=NULL;
return head;
}
};
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode *rotateRight(ListNode *head, int k)
{
if(head==NULL || k==0) return head;
//n
ListNode *p=head;
int n=0;
while(p!=NULL)
{
n++;
p=p->next;
}
k=k%n;
if(k==0) return head;
ListNode* p1=head;
ListNode* p2=head;
for(int i=0;i<k;i++) p2=p2->next;
while(p2->next!=NULL)
{
p2=p2->next;
p1=p1->next;
}
p2->next=head;
head=p1->next;
p1->next=NULL;
return head;
}
};