Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists.
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode *mergeTwoLists(ListNode *l1, ListNode *l2)
{
if(l1==NULL && l2==NULL)
return NULL;
ListNode* head;
head=GetNum(l1,l2);
ListNode* p=head;
while(l1!=NULL || l2!=NULL)
{
p->next=GetNum(l1,l2);
p=p->next;
}
return head;
}
ListNode* GetNum(ListNode* &l1,ListNode* &l2)
{
if(l1==NULL)
{
ListNode* p=l2;
l2=l2->next;
return p;
}
if(l2==NULL)
{
ListNode* p=l1;
l1=l1->next;
return p;
}
if(l1->val<l2->val)
{
ListNode* p=l1;
l1=l1->next;
return p;
}
if(l1->val>=l2->val)
{
ListNode* p=l2;
l2=l2->next;
return p;
}
}
};
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode(int x) : val(x), next(NULL) {}
* };
*/
class Solution {
public:
ListNode *mergeTwoLists(ListNode *l1, ListNode *l2)
{
if(l1==NULL && l2==NULL)
return NULL;
ListNode* head;
head=GetNum(l1,l2);
ListNode* p=head;
while(l1!=NULL || l2!=NULL)
{
p->next=GetNum(l1,l2);
p=p->next;
}
return head;
}
ListNode* GetNum(ListNode* &l1,ListNode* &l2)
{
if(l1==NULL)
{
ListNode* p=l2;
l2=l2->next;
return p;
}
if(l2==NULL)
{
ListNode* p=l1;
l1=l1->next;
return p;
}
if(l1->val<l2->val)
{
ListNode* p=l1;
l1=l1->next;
return p;
}
if(l1->val>=l2->val)
{
ListNode* p=l2;
l2=l2->next;
return p;
}
}
};