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  • Minimum Path Sum

    Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path.

    Note: You can only move either down or right at any point in time.

    class Solution {
    public:
        int minPathSum(vector<vector<int> > &grid) {
            if(grid.size()==0 || grid[0].size()==0return 0;
            int min[grid[0].size()];
            min[0]=grid[0][0];
            for(int i=1;i<grid[0].size();i++)
                min[i]=min[i-1]+grid[0][i];
            for(int i=1;i<grid.size();i++)
            {
                min[0]=min[0]+grid[i][0];
                for(int j=1;j<grid[0].size();j++)
                {
                    int sum1=min[j]+grid[i][j];
                    int sum2=min[j-1]+grid[i][j];
                    min[j]=sum1;
                    if(sum1>sum2) min[j]=sum2;
                }
            }
            return min[grid[0].size()-1];
        }
    }; 
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  • 原文地址:https://www.cnblogs.com/erictanghu/p/3759454.html
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