Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:
- Integers in each row are sorted from left to right.
- The first integer of each row is greater than the last integer of the previous row.
For example,
Consider the following matrix:
[ [1, 3, 5, 7], [10, 11, 16, 20], [23, 30, 34, 50] ]
Given target = 3
, return true
.
class Solution {
public:
bool searchMatrix(vector<vector<int> > &matrix, int target) {
int xlen=matrix.size();
if(xlen==0) return false;
int ylen=matrix[0].size();
if(ylen==0) return false;
int index=xlen-1;
while(index>=0 && matrix[index][0]>target)
index--;
if(index==-1) return false;
vector<int>* v=&(matrix[index]);
index=ylen-1;
while(index>=0 && (*v)[index]!=target)
index--;
if(index==-1) return false;
return true;
}
};
public:
bool searchMatrix(vector<vector<int> > &matrix, int target) {
int xlen=matrix.size();
if(xlen==0) return false;
int ylen=matrix[0].size();
if(ylen==0) return false;
int index=xlen-1;
while(index>=0 && matrix[index][0]>target)
index--;
if(index==-1) return false;
vector<int>* v=&(matrix[index]);
index=ylen-1;
while(index>=0 && (*v)[index]!=target)
index--;
if(index==-1) return false;
return true;
}
};