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  • Longest Consecutive Sequence

    Given an unsorted array of integers, find the length of the longest consecutive elements sequence.

    For example,
    Given [100, 4, 200, 1, 3, 2],
    The longest consecutive elements sequence is [1, 2, 3, 4]. Return its length: 4.

    Your algorithm should run in O(n) complexity.

    class Solution {
    public:
        int longestConsecutive(vector<int> &num) 
        {                  
            int n=num.size();
            vector<int> v1;
            vector<int> v2;        
            for(int i=0;i<n;i++)
                if(num[i]<0) v1.push_back(num[i]);
                else v2.push_back(num[i]);
            radixsort(v1);
            radixsort(v2);
            for(int i=0;i<v1.size();i++)
                num[i]=v1[v1.size()-i-1];
            for(int i=0;i<v2.size();i++)
                num[i+v1.size()]=v2[i];
            
            //get the longest
            int longest=1;
            int index=0;
            while(true)
            {
                if(index+1>=n) break;
                int con=1;
                int index2=index;
                while(index2+1<n && (num[index2+1]==num[index2] || num[index2+1]==num[index2]+1))
                {
                    if(num[index2+1]==num[index2]+1) con++;
                    index2++;
                }
                if(con>longest) longest=con;
                index=index2+1;                    
            }
            return longest;
        }
    
        void radixsort(vector<int> &num)
        {
            int n=num.size();
            int* data=(int*)malloc(n*sizeof(int));
            int d=1;
            int radix=10;
            int* bulk=(int*)malloc(radix*sizeof(int));
            //radix sort
            for(int k=0;k<10;k++)
            {
                for(int i=0;i<radix;i++) bulk[i]=0;
                for(int i=0;i<n;i++)
                {
                    int ibulk=num[i]/d%radix;
                    if(ibulk<0) ibulk=-ibulk;
                    bulk[ibulk]++;
                }
                    
                int step=bulk[0];
                bulk[0]=0;
                for(int i=1;i<radix;i++)
                {
                    int step2=bulk[i];
                    bulk[i]=bulk[i-1]+step;
                    step=step2;
                }
                
                for(int i=0;i<n;i++)
                {
                    int ibulk=num[i]/d%radix;
                    if(ibulk<0) ibulk=-ibulk;
                    data[bulk[ibulk]]=num[i];
                    bulk[ibulk]++;
                }
    
                for(int i=0;i<n;i++)
                    num[i]=data[i];
                    
                d=d*radix;
            }
            free(data);
            free(bulk);
        }
    };
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  • 原文地址:https://www.cnblogs.com/erictanghu/p/3759679.html
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