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  • Python3之Zip

    from collections import defaultdict
    from collections import OrderedDict
    
    d = defaultdict(list)
    d['a'].append(1)
    d['a'].append(2)
    d['b'].append(5)
    
    print(d)
    
    #di = dict(list)
    #di['b'].append(11)
    #di['b'].append(22)
    #di['c'].append(55)
    #print(di)
    
    ds = defaultdict(set)
    ds['b'].add(11)
    ds['b'].add(22)
    ds['c'].add(33)
    print(ds)
    
    do = OrderedDict()
    do['foo'] = 1
    do['far'] = 2
    do['coo'] = 5
    
    for key in do:
        print(key, do[key])
    
    # 字典的运算
    prices = {
        'IBM': 205.5,
        'APPLE': 500,
        'HP': 43,
        'FB': 88.3
    }
    
    min_prices = min(zip(prices.values(), prices.keys()))
    print(min_prices)
    
    max_prices = max(zip(prices.values(), prices.keys()))
    print(max_prices)
    
    prices_sorted = sorted(zip(prices.values(), prices.keys()))
    print(prices_sorted)
    
    z1 = [1,2,3]
    z2 = ['A','B','C']
    z3 = zip(z1, z2)
    print(list(z3))
    z4 = zip(*zip(z1, z2))
    print(list(z4))
    
    x = [1,2]
    y = ['a','b','c']
    print(list(zip(x,y)))
    
    #zip()配合*号操作符,可以将已经zip过的列表对象解压, 并且返回的是元祖
    
    
    #使用zip和iterators生成滑动窗口 (n -grams) 
    from itertools import islice
    def n_grams(a, n):
        z = (islice(a, i, None) for i in range(n))
        return zip(*z)
    
    a = [1,2,3,4,5,6]
    print('(a,3):',list(n_grams(a,3)))
    print('(a,2):',list(n_grams(a,2)))
    print('(a,4):',list(n_grams(a,4)))
    
    # 使用zip反转字典
    m = {'a': 1, 'b': 2, 'c': 3, 'd': 4}
    print('m.items = ', m.items())
    print(list(zip(m.values(), m.keys())))
    md = dict(zip(m.values(), m.keys()))
    print(md)
    

      

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  • 原文地址:https://www.cnblogs.com/eternal1025/p/5227257.html
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