【题目链接】
【算法】
数位DP
【代码】
#include<bits/stdc++.h> using namespace std; #define MAXL 15 typedef unsigned long long ULL; ULL T,n,a[MAXL]; ULL dp[MAXL][10]; template <typename T> inline void read(T &x) { ULL f = 1; x = 0; char c = getchar(); for (; !isdigit(c); c = getchar()) { if (c == '-') f = -f; } for (; isdigit(c); c = getchar()) x = (x << 3) + (x << 1) + c -'0'; x *= f; } template <typename T> inline void write(T x) { if (x < 0) { putchar('-'); x = -x; } if (x > 9) write(x/10); putchar(x%10+'0'); } template <typename T> inline void writeln(T x) { write(x); puts(""); } inline void getdp() { ULL i,j,k; dp[0][0] = 1; for (i = 1; i <= MAXL; i++) { for (j = 0; j <= 9; j++) { for (k = 0; k <= 9; k++) { if (j == 4 && k == 9) continue; dp[i][j] += dp[i-1][k]; } } } } inline ULL calc(ULL n) { ULL i,j,ans = 0; a[0] = 0; while (n != 0) { a[++a[0]] = n % 10; n /= 10; } a[a[0]+1] = 0; for (i = a[0]; i >= 1; i--) { for (j = 0; j < a[i]; j++) { if (a[i+1] == 4 && j == 9) continue; ans += dp[i][j]; } if (a[i+1] == 4 && a[i] == 9) break; } return ans; } int main() { getdp(); read(T); while (T--) { read(n); writeln(n-calc(n+1)+1); } return 0; }