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  • 【USACO06NOV】路障

    【题目链接】

              点击打开链接

    【算法】

             最短路

    【代码】

               

    #include<bits/stdc++.h>
    using namespace std;
    #define MAXN 5000
    #define MAXM 100000
    
    int i,N,M,shortest,ans;
    int dista[MAXN+10],distb[MAXN+10],x[MAXM+10],y[MAXM+10],d[MAXM+10],
            visa[MAXN+10],visb[MAXN+10];
    vector<pair<int,int> > E[MAXN+10];
     
    template <typename T> void read(T &x) {
            int f=1; char c = getchar(); x=0;
            for (; !isdigit(c); c = getchar()) { if (c=='-') f=-1; }
            for (; isdigit(c); c = getchar()) x=x*10+c-'0';
            x*=f;
    }
    
    inline void dijkstra1() {
            int i,x,to;
            priority_queue<pair<int,int> > q;
            for (i = 2; i <= N; i++) dista[i] = 2e9;
            q.push(make_pair(-0,1));
            while (!q.empty()) {
                    x = q.top().second; q.pop();
                    if (visa[x]) continue;
                    visa[x] = 1;
                    for (i = 0; i < E[x].size(); i++) {
                            to = E[x][i].first;
                            if (dista[x] + E[x][i].second < dista[to]) {
                                    dista[to] = dista[x] + E[x][i].second;
                                    q.push(make_pair(-dista[to],to));
                            }
                    }
            }
    }
    
    inline void dijkstra2() {
            int i,x,to;
            priority_queue<pair<int,int> > q;
            for (i = 1; i < N; i++) distb[i] = 2e9;
            q.push(make_pair(-0,N));
            while (!q.empty()) {
                    x = q.top().second; q.pop();
                    if (visb[x]) continue;
                    visb[x] = 1;
                    for (i = 0; i < E[x].size(); i++) {
                            to = E[x][i].first;
                            if (distb[x] + E[x][i].second < distb[to]) {
                                    distb[to] = distb[x] + E[x][i].second;
                                    q.push(make_pair(-distb[to],to));
                            }
                    }
            }
    } 
    
    int main() {
            
            read(N); read(M);
            
            for (i = 1; i <= M; i++) {
                    read(x[i]); read(y[i]); read(d[i]);
                    E[x[i]].push_back(make_pair(y[i],d[i]));
                    E[y[i]].push_back(make_pair(x[i],d[i]));    
            }
            
            dijkstra1();
            dijkstra2();
            
            shortest = dista[N];
            ans = 2e9;
            
            for (i = 1; i <= M; i++) {
                    if (dista[x[i]] + d[i] + distb[y[i]] > shortest)
                            ans = min(ans,dista[x[i]]+d[i]+distb[y[i]]);    
                    if (dista[y[i]] + d[i] + distb[x[i]] > shortest)
                            ans = min(ans,dista[y[i]]+d[i]+distb[x[i]]);    
            }
            
            cout<< ans << endl;
            
            return 0;
        
    }
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  • 原文地址:https://www.cnblogs.com/evenbao/p/9196395.html
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