【题目链接】
http://poj.org/problem?id=1475
【算法】
双重BFS
【代码】
#include <algorithm> #include <bitset> #include <cctype> #include <cerrno> #include <clocale> #include <cmath> #include <complex> #include <cstdio> #include <cstdlib> #include <cstring> #include <ctime> #include <deque> #include <exception> #include <fstream> #include <functional> #include <limits> #include <list> #include <map> #include <iomanip> #include <ios> #include <iosfwd> #include <iostream> #include <istream> #include <ostream> #include <queue> #include <set> #include <sstream> #include <stdexcept> #include <streambuf> #include <string> #include <utility> #include <vector> #include <cwchar> #include <cwctype> #include <stack> #include <limits.h> using namespace std; #define MAXN 30 int n,m,i,j,px,py,bx,by,ex,ey,TC; string t; char mp[MAXN][MAXN]; bool visited1[MAXN][MAXN],visited2[MAXN][MAXN]; const int dx[4] = {0,0,-1,1}; const int dy[4] = {-1,1,0,0}; const char box_path[5] = "WENS"; const char people_path[5] = "wens"; struct Box { int bx,by,px,py; string path; }; struct People { int x,y; string path; }; inline bool ok(int x,int y) { return x >= 1 && x <= n && y >= 1 && y <= m; } inline bool bfs2(int sx,int sy,int ex,int ey,int nx,int ny) { int i,tx,ty; People cur; queue< People > q; while (!q.empty()) q.pop(); memset(visited2,false,sizeof(visited2)); q.push((People){sx,sy,""}); while (!q.empty()) { cur = q.front(); q.pop(); if (cur.x == ex && cur.y == ey) { t = cur.path; return true; } for (i = 0; i < 4; i++) { tx = cur.x + dx[i]; ty = cur.y + dy[i]; if (ok(tx,ty) && !visited2[tx][ty] && mp[tx][ty] != '#') { if (tx == nx && ty == ny) continue; visited2[tx][ty] = true; q.push((People){tx,ty,cur.path+people_path[i]}); } } } return false; } inline void bfs1() { int i,tx,ty; queue<Box> q; Box cur; memset(visited1,false,sizeof(visited1)); while (!q.empty()) q.pop(); q.push((Box){bx,by,px,py,""}); while (!q.empty()) { cur = q.front(); q.pop(); if (cur.bx == ex && cur.by == ey) { cout<< cur.path << endl; return; } for (i = 0; i < 4; i++) { tx = cur.bx + dx[i]; ty = cur.by + dy[i]; if (ok(tx,ty) && !visited1[tx][ty] && mp[tx][ty] != '#') { if (bfs2(cur.px,cur.py,cur.bx-dx[i],cur.by-dy[i],cur.bx,cur.by)) { visited1[tx][ty] = true; q.push((Box){tx,ty,cur.bx,cur.by,cur.path+t+box_path[i]}); } } } } printf("Impossible. "); } int main() { while (scanf("%d%d",&n,&m) != EOF && n && m) { getchar(); for (i = 1; i <= n; i++) { for (j = 1; j <= m; j++) { mp[i][j] = getchar(); if (mp[i][j] == 'S') { px = i; py = j; } if (mp[i][j] == 'B') { bx = i; by = j; } if (mp[i][j] == 'T') { ex = i; ey = j; } } getchar(); } printf("Maze #%d ",++TC); bfs1(); printf(" "); } return 0; }