zoukankan      html  css  js  c++  java
  • [POJ 1041] John's Trip

    [题目链接]

             http://poj.org/problem?id=1041

    [算法]

            欧拉回路
    [代码]

            

    #include <algorithm>  
    #include <bitset>  
    #include <cctype>  
    #include <cerrno>  
    #include <clocale>  
    #include <cmath>  
    #include <complex>  
    #include <cstdio>  
    #include <cstdlib>  
    #include <cstring>  
    #include <ctime>  
    #include <deque>  
    #include <exception>  
    #include <fstream>  
    #include <functional>  
    #include <limits>  
    #include <list>  
    #include <map>  
    #include <iomanip>  
    #include <ios>  
    #include <iosfwd>  
    #include <iostream>  
    #include <istream>  
    #include <ostream>  
    #include <queue>  
    #include <set>  
    #include <sstream>  
    #include <stdexcept>  
    #include <streambuf>  
    #include <string>  
    #include <utility>  
    #include <vector>  
    #include <cwchar>  
    #include <cwctype>  
    #include <stack>  
    #include <limits.h>
    using namespace std;
    #define MAXN 2010
    #define MAXM 45
    
    int i,u,v,cnt,max_id,id;
    int degree[MAXN],ans[MAXN];
    bool visited[MAXN];
    pair<int,int> e[MAXN];
    bool flag;
    
    inline void dfs(int u)
    {
            int i,v;
            for (i = 1; i <= max_id; i++)
            {
                    if (!visited[i] && (e[i].first == u || e[i].second == u))
                    {
                            visited[i] = true;
                            dfs(e[i].first + e[i].second - u);
                            ans[++cnt] = i;
                    }        
            }        
    }
    
    int main() 
    {
            
            while (scanf("%d%d",&u,&v) != EOF)
            {
                    if (!u && !v) break;
                    max_id = 0;
                    memset(degree,false,sizeof(degree));
                    memset(visited,false,sizeof(visited));
                    scanf("%d",&id);
                    max_id = max(max_id,id);
                    e[id] = make_pair(u,v);
                    degree[u]++; degree[v]++;
                    while (scanf("%d%d",&u,&v) && (u || v))
                    {
                            scanf("%d",&id);
                            e[id] = make_pair(u,v);
                            max_id = max(max_id,id);
                            degree[u]++; degree[v]++;
                    }
                    flag = false;
                    for (i = 1; i <= 50; i++)
                    {
                            if (degree[i] & 1)
                            {
                                    flag = true;
                                    break;
                            }
                    }
                    if (flag)
                    {
                            printf("Round trip does not exist.
    ");
                            continue;
                    }
                    cnt = 0;
                    dfs(1);
                    for (i = cnt; i >= 1; i--) printf("%d ",ans[i]);
                    printf("
    ");
            }
            
            return 0;
        
    }
  • 相关阅读:
    POJ 3616 Milking Time(简单DP)
    POJ 2954 Triangle(计算几何Pick定理)
    POJ 3664 Election Time(简单的快速排序)
    POJ 2007 Scrambled Polygon(计算几何凸包)
    POJ 3673 Cow Multiplication(简单数学)
    POJ 3663 Costume Party (快速排序)
    计算几何模板(一)
    [转]Silverlight中使用MVVM(3)
    Silverlight中使用MVVM(2)
    Silverlight使用Binding动态绑定数据
  • 原文地址:https://www.cnblogs.com/evenbao/p/9435671.html
Copyright © 2011-2022 走看看