zoukankan html css js c++ java

人生第一道cf的题

Array of integers is unimodal, if:

it is strictly increasing in the beginning;
after that it is constant;
after that it is strictly decreasing.

The first block (increasing) and the last block (decreasing) may be absent. It is allowed that both of this blocks are absent.

For example, the following three arrays are unimodal: [5, 7, 11, 11, 2, 1], [4, 4, 2], [7], but the following three are not unimodal: [5, 5, 6, 6, 1], [1, 2, 1, 2], [4, 5, 5, 6].

Write a program that checks if an array is unimodal.

Input

The first line contains integer n (1 ≤ n ≤ 100) — the number of elements in the array.

The second line contains n integers a1, a2, ..., an (1 ≤ ai ≤ 1 000) — the elements of the array.

Output

Print "YES" if the given array is unimodal. Otherwise, print "NO".

You can output each letter in any case (upper or lower).

Examples

input

6
1 5 5 5 4 2

output

YES

input

5
10 20 30 20 10

output

YES

input

4
1 2 1 2

output

NO

input

7
3 3 3 3 3 3 3

output

YES

Note

In the first example the array is unimodal, because it is strictly increasing in the beginning (from position 1 to position 2, inclusively), that it is constant (from position 2 to position 4, inclusively) and then it is strictly decreasing (from position 4 to position 6, inclusively).

 1 // ab.cpp : 定义控制台应用程序的入口点。
 2 //
 3 
 4 #include "stdio.h"
 5 #include<iostream>
 6 using namespace std;
 7 bool is_Unimodal (int n)
 8 {
 9     int num_before;
10     int num;
11     int flag=1;
12     num_before=num=0;
13     for(int i=1; i<=n; i++)
14     {
15         scanf("%d",&num);
16         if(i==1)
17         {
18             num_before=num;
19         }
20         else
21         {
22             if(num_before<num&&flag==1)
23             {
24                 num_before=num;
25 
26                 continue;
27 
28             }
29 
30             if(flag==1&&num_before==num)
31             {
32                 flag=2;
33                 num_before=num;
34 
35                 continue;
36             }
37 
38 
39             if(flag==2&&num_before==num)
40             {
41                 num_before=num;
42 
43                 continue;
44             }
45             if(flag==1&&num_before>num)
46             {
47                 flag=3;
48                 num_before=num;
49 
50                 continue;
51             }
52             if(flag==2&&num_before>num)
53             {
54                 flag=3;
55                 num_before=num;
56 
57                 continue;
58             }
59             if(flag==3&&num_before>num)
60             {
61                 num_before=num;
62 
63                 continue;
64             }
65             flag=0;
66         }
67 
68     }
69 
70     if(flag==0)
71         return false;
72     else
73         return true;
74 }
75 int main()
76 {
77     int n;
78     scanf("%d",&n);
79     cout<<(is_Unimodal (n)?"YES":"NO")<<endl;
80     return 0;
81 }

查看全文

相关阅读:
nginx反向代理配置去除前缀
 centos6.x yum源站失效
 Shell if 条件判断
 使用Shell显示脚本使用帮助
 libmysqlclient.so.20 错误问题解决
 linux中ldconfig的使用介绍
 【源码解读】Vue与ASP.NET Core WebAPI的集成
 【Golang】快速复习指南QuickReview（十一）——数据库访问(MySql为例)
【Golang】快速复习指南QuickReview（十）——goroutine池
 【Golang】快速复习指南QuickReview（九）——socket

原文地址：https://www.cnblogs.com/fairy-wzp/p/7197355.html