Given a binary tree, find the length of the longest path where each node in the path has the same value. This path may or may not pass through the root.
Note: The length of path between two nodes is represented by the number of edges between them.
Example 1:
Input:
5 / 4 5 / 1 1 5
Output:
2
Example 2:
Input:
1 / 4 5 / 4 4 5
Output:
2
Note: The given binary tree has not more than 10000 nodes. The height of the tree is not more than 1000.
time: O(n), space: O(height)
/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ class Solution { int length = 0; public int longestUnivaluePath(TreeNode root) { if(root == null) { return 0; } helper(root); return length; } public int helper(TreeNode root) { if(root == null) { return 0; } int l = helper(root.left); int r = helper(root.right); int left = 0, right = 0; if(root.left != null && root.val == root.left.val) { left = l + 1; } if(root.right != null && root.val == root.right.val) { right = r + 1; } length = Math.max(length, left + right); return Math.max(left, right); } }