zoukankan      html  css  js  c++  java
  • 1103. Distribute Candies to People

    We distribute some number of candies, to a row of n = num_people people in the following way:

    We then give 1 candy to the first person, 2 candies to the second person, and so on until we give n candies to the last person.

    Then, we go back to the start of the row, giving n + 1 candies to the first person, n + 2 candies to the second person, and so on until we give 2 * n candies to the last person.

    This process repeats (with us giving one more candy each time, and moving to the start of the row after we reach the end) until we run out of candies.  The last person will receive all of our remaining candies (not necessarily one more than the previous gift).

    Return an array (of length num_people and sum candies) that represents the final distribution of candies.

    Example 1:

    Input: candies = 7, num_people = 4
    Output: [1,2,3,1]
    Explanation:
    On the first turn, ans[0] += 1, and the array is [1,0,0,0].
    On the second turn, ans[1] += 2, and the array is [1,2,0,0].
    On the third turn, ans[2] += 3, and the array is [1,2,3,0].
    On the fourth turn, ans[3] += 1 (because there is only one candy left), and the final array is [1,2,3,1].
    

    Example 2:

    Input: candies = 10, num_people = 3
    Output: [5,2,3]
    Explanation: 
    On the first turn, ans[0] += 1, and the array is [1,0,0].
    On the second turn, ans[1] += 2, and the array is [1,2,0].
    On the third turn, ans[2] += 3, and the array is [1,2,3].
    On the fourth turn, ans[0] += 4, and the final array is [5,2,3].
    

    Constraints:

    • 1 <= candies <= 10^9
    • 1 <= num_people <= 1000

    time = O(n), space = O(n)

    class Solution {
        public int[] distributeCandies(int candies, int num_people) {
            int[] res = new int[num_people];
            for(int i = 0; candies > 0; candies -= i) {
                res[i % num_people] += Math.min(++i, candies);
            }
            return res;
        }
    }
  • 相关阅读:
    程序开发
    主方法
    日志
    node.js
    二维互换
    前台打断点
    具体的后台断点快捷键
    Jenkins
    断点
    循环
  • 原文地址:https://www.cnblogs.com/fatttcat/p/13534715.html
Copyright © 2011-2022 走看看