shell 判断变量类型的几种方法
方法一
脚本如下
#!/usr/bin/env bash
function check(){
local a="$1"
printf "%d" "$a" &>/dev/null && echo "integer" && return
printf "%d" "$(echo $a|sed 's/^[+-]?0+//')" &>/dev/null && echo "integer" && return
printf "%f" "$a" &>/dev/null && echo "number" && return
[ ${#a} -eq 1 ] && echo "char" && return
echo "string"
}
echo ". is" $(check ".")
echo "1 is" $(check "1")
echo ".1 is" $(check ".1")
echo "1. is" $(check "1.")
echo "1234 is" $(check "1234")
echo "1.234 is" $(check "1.234")
echo "1.2.3.4 is" $(check "1.2.3.4")
echo "a1234 is" $(check "a1234")
echo "abc is" $(check "abc")
echo "a is" $(check "a")
echo "1e+2" $(check "1e+2")
echo "1.e+2" $(check "1e+2")
echo ".1e+2" $(check "1e+2")
echo "-1" $(check "-1")
echo "-1.2" $(check "-1.2")
echo "-a" $(check "-a")
echo "0x1f" $(check "0x1f")
echo "0x1H" $(check "0x1H")
echo "0333" $(check "0333")
echo "0999" $(check "0999")
echo "+003" $(check "+003")
echo "+003.3" $(check "+003.3")
输出结果如下:
. is char
1 is integer
.1 is number
1. is number
1234 is integer
1.234 is number
1.2.3.4 is string
a1234 is string
abc is string
a is char
1e+2 number
1.e+2 number
.1e+2 number
-1 integer
-1.2 number
-a string
0x1f integer
0x1H string
0333 integer
0999 number
+003 integer
+003.3 number
方法二
#!/bin/bash
#
echo $a|grep [a-zA-Z]>/dev/null
if [ $? -eq 0 ];then
echo "string"
else
echo "data"
fi
方法三
#!/bin/bash
#
if [[ $a != *[^0-9]* ]]&&[[ $a != 0* ]]
then
echo $a is data
else
echo $a is string
fi
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原文链接:https://blog.csdn.net/qq_17528659/java/article/details/87183363