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  • leetcode -- Valid Parentheses

    Given a string containing just the characters '('')''{''}''[' and ']', determine if the input string is valid.

    The brackets must close in the correct order, "()" and "()[]{}" are all valid but "(]" and "([)]" are not.

    思路:使用栈,java Stack类中 peek方法是查看栈顶元素而不移除它

     1 public class Solution {
     2     public boolean isValid(String s) {
     3         // Start typing your Java solution below
     4         // DO NOT write main() function
     5         Stack<Character> stack = new Stack<Character>();
     6         int len = s.length();
     7         boolean flag = false;
     8         for(int i = 0; i < len; i++){
     9             if(!stack.empty()){
    10                 char top = stack.peek();
    11                 char c = s.charAt(i);
    12      
    13                 if(!match(top, c))
    14                     stack.push(c);
    15                 else{
    16                     stack.pop();
    17                 }
    18             } else {
    19                 char c = s.charAt(i);
    20                 stack.push(c);
    21             }
    22         }
    23         
    24         if(!stack.empty())
    25             return flag;
    26         else{
    27             flag = true;
    28             return flag;
    29         }
    30     }
    31     
    32     boolean match(char a, char b){
    33         if(a == '(' && b == ')'){
    34             return true;
    35         } else if(a == '{' && b == '}'){
    36             return true;
    37         } else if(a == '[' && b == ']'){
    38             return true;
    39         } else {
    40             return false;
    41         }
    42     }
    43 }
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  • 原文地址:https://www.cnblogs.com/feiling/p/3189349.html
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