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  • leetcode -- Unique Paths II

    Follow up for "Unique Paths":

    Now consider if some obstacles are added to the grids. How many unique paths would there be?

    An obstacle and empty space is marked as 1 and 0 respectively in the grid.

    For example,

    There is one obstacle in the middle of a 3x3 grid as illustrated below.

    [
      [0,0,0],
      [0,1,0],
      [0,0,0]
    ]
    

    The total number of unique paths is 2.

    Note: m and n will be at most 100.

    [解题思路]

    本题与上题思路差不多,直接使用DP来解,唯一区别在对obstacle的处理上,当遇到obstacle时将该位置置为0

    表示该位置不可以到达[m][n]

     1 public int uniquePathsWithObstacles(int[][] obstacleGrid) {
     2         // Start typing your Java solution below
     3         // DO NOT write main() function
     4         int m = obstacleGrid.length;
     5         int n = obstacleGrid[0].length;
     6         int[][] steps = new int[m+2][n+2];
     7         for(int i = 0; i < m; i++){
     8             for(int j = 0; j < n; j++){
     9                 steps[i][j] = 0;
    10             }
    11         }
    12         steps[m][n+1] = 1;
    13         for(int i = m; i >= 1; i--){
    14             for(int j = n; j >= 1; j--){
    15                 if(obstacleGrid[i - 1][j - 1] == 1){
    16                     steps[i][j] = 0;
    17                     continue;
    18                 }
    19                 steps[i][j] = steps[i+1][j] + steps[i][j+1];
    20             }
    21         }
    22         return steps[1][1];
    23     }
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  • 原文地址:https://www.cnblogs.com/feiling/p/3271548.html
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