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  • MYSQL

    -- 1、查询"01"课程比"02"课程成绩高的学生的信息及课程分数

    select a.* ,b.s_score as 01_score,c.s_score as 02_score from
    student a
    join score b on a.s_id=b.s_id and b.c_id='01'
    left join score c on a.s_id=c.s_id and c.c_id='02' or c.c_id = NULL where b.s_score>c.s_score


    -- 2、查询"01"课程比"02"课程成绩低的学生的信息及课程分数

    select a.* ,b.s_score as 01_score,c.s_score as 02_score from
    student a left join score b on a.s_id=b.s_id and b.c_id='01' or b.c_id=NULL
    join score c on a.s_id=c.s_id and c.c_id='02' where b.s_score<c.s_score


    -- 3、查询平均成绩大于等于60分的同学的学生编号和学生姓名和平均成绩
    select b.s_id,b.s_name,ROUND(AVG(a.s_score),2) as avg_score from
    student b
    join score a on b.s_id = a.s_id
    GROUP BY b.s_id,b.s_name HAVING ROUND(AVG(a.s_score),2)>=60;


    -- 4、查询平均成绩小于60分的同学的学生编号和学生姓名和平均成绩
    -- (包括有成绩的和无成绩的)

    select b.s_id,b.s_name,ROUND(AVG(a.s_score),2) as avg_score from
    student b
    left join score a on b.s_id = a.s_id
    GROUP BY b.s_id,b.s_name HAVING ROUND(AVG(a.s_score),2)<60
    union
    select a.s_id,a.s_name,0 as avg_score from
    student a
    where a.s_id not in (
    select distinct s_id from score);


    -- 5、查询所有同学的学生编号、学生姓名、选课总数、所有课程的总成绩
    select a.s_id,a.s_name,count(b.c_id) as sum_course,sum(b.s_score) as sum_score from
    student a
    left join score b on a.s_id=b.s_id
    GROUP BY a.s_id,a.s_name;


    -- 6、查询"李"姓老师的数量
    select count(t_id) from teacher where t_name like '李%';

    -- 7、查询学过"张三"老师授课的同学的信息
    select a.* from
    student a
    join score b on a.s_id=b.s_id where b.c_id in(
    select c_id from course where t_id =(
    select t_id from teacher where t_name = '张三'));

    -- 8、查询没学过"张三"老师授课的同学的信息
    select * from
    student c
    where c.s_id not in(
    select a.s_id from student a join score b on a.s_id=b.s_id where b.c_id in(
    select c_id from course where t_id =(
    select t_id from teacher where t_name = '张三')));
    -- 9、查询学过编号为"01"并且也学过编号为"02"的课程的同学的信息

    select a.* from
    student a,score b,score c
    where a.s_id = b.s_id and a.s_id = c.s_id and b.c_id='01' and c.c_id='02';

    -- 10、查询学过编号为"01"但是没有学过编号为"02"的课程的同学的信息

    select a.* from
    student a
    where a.s_id in (select s_id from score where c_id='01' ) and a.s_id not in(select s_id from score where c_id='02')


    -- 11、查询没有学全所有课程的同学的信息

    select s.* from
    student s where s.s_id in(
    select s_id from score where s_id not in(
    select a.s_id from score a
    join score b on a.s_id = b.s_id and b.c_id='02'
    join score c on a.s_id = c.s_id and c.c_id='03'
    where a.c_id='01'))

    -- 12、查询至少有一门课与学号为"01"的同学所学相同的同学的信息

    select * from student where s_id in(
    select distinct a.s_id from score a where a.c_id in(select a.c_id from score a where a.s_id='01')
    );

    -- 13、查询和"01"号的同学学习的课程完全相同的其他同学的信息

    select a.* from student a where a.s_id in(
    select distinct s_id from score where s_id!='01' and c_id in(select c_id from score where s_id='01')
    group by s_id
    having count(1)=(select count(1) from score where s_id='01'));
    -- 14、查询没学过"张三"老师讲授的任一门课程的学生姓名
    select a.s_name from student a where a.s_id not in (
    select s_id from score where c_id =
    (select c_id from course where t_id =(
    select t_id from teacher where t_name = '张三'))
    group by s_id);

    -- 15、查询两门及其以上不及格课程的同学的学号,姓名及其平均成绩
    select a.s_id,a.s_name,ROUND(AVG(b.s_score)) from
    student a
    left join score b on a.s_id = b.s_id
    where a.s_id in(
    select s_id from score where s_score<60 GROUP BY s_id having count(1)>=2)
    GROUP BY a.s_id,a.s_name

    -- 16、检索"01"课程分数小于60,按分数降序排列的学生信息
    select a.*,b.c_id,b.s_score from
    student a,score b
    where a.s_id = b.s_id and b.c_id='01' and b.s_score<60 ORDER BY b.s_score DESC;

    -- 17、按平均成绩从高到低显示所有学生的所有课程的成绩以及平均成绩
    select a.s_id,(select s_score from score where s_id=a.s_id and c_id='01') as 语文,
    (select s_score from score where s_id=a.s_id and c_id='02') as 数学,
    (select s_score from score where s_id=a.s_id and c_id='03') as 英语,
    round(avg(s_score),2) as 平均分 from score a GROUP BY a.s_id ORDER BY 平均分 DESC;

    -- 18.查询各科成绩最高分、最低分和平均分:以如下形式显示:课程ID,课程name,最高分,最低分,平均分,及格率,中等率,优良率,优秀率
    --及格为>=60,中等为:70-80,优良为:80-90,优秀为:>=90
    select a.c_id,b.c_name,MAX(s_score),MIN(s_score),ROUND(AVG(s_score),2),
    ROUND(100*(SUM(case when a.s_score>=60 then 1 else 0 end)/SUM(case when a.s_score then 1 else 0 end)),2) as 及格率,
    ROUND(100*(SUM(case when a.s_score>=70 and a.s_score<=80 then 1 else 0 end)/SUM(case when a.s_score then 1 else 0 end)),2) as 中等率,
    ROUND(100*(SUM(case when a.s_score>=80 and a.s_score<=90 then 1 else 0 end)/SUM(case when a.s_score then 1 else 0 end)),2) as 优良率,
    ROUND(100*(SUM(case when a.s_score>=90 then 1 else 0 end)/SUM(case when a.s_score then 1 else 0 end)),2) as 优秀率
    from score a left join course b on a.c_id = b.c_id GROUP BY a.c_id,b.c_name

    -- 19、按各科成绩进行排序,并显示排名(实现不完全)
    -- mysql没有rank函数
    select a.s_id,a.c_id,
    @i:=@i +1 as i保留排名,
    @k:=(case when @score=a.s_score then @k else @i end) as rank不保留排名,
    @score:=a.s_score as score
    from (
    select s_id,c_id,s_score from score WHERE c_id='01' GROUP BY s_id,c_id,s_score ORDER BY s_score DESC
    )a,(select @k:=0,@i:=0,@score:=0)s
    union
    select a.s_id,a.c_id,
    @i:=@i +1 as i,
    @k:=(case when @score=a.s_score then @k else @i end) as rank,
    @score:=a.s_score as score
    from (
    select s_id,c_id,s_score from score WHERE c_id='02' GROUP BY s_id,c_id,s_score ORDER BY s_score DESC
    )a,(select @k:=0,@i:=0,@score:=0)s
    union
    select a.s_id,a.c_id,
    @i:=@i +1 as i,
    @k:=(case when @score=a.s_score then @k else @i end) as rank,
    @score:=a.s_score as score
    from (
    select s_id,c_id,s_score from score WHERE c_id='03' GROUP BY s_id,c_id,s_score ORDER BY s_score DESC
    )a,(select @k:=0,@i:=0,@score:=0)s

    -- 20、查询学生的总成绩并进行排名
    select a.s_id,
    @i:=@i+1 as i,
    @k:=(case when @score=a.sum_score then @k else @i end) as rank,
    @score:=a.sum_score as score
    from (select s_id,SUM(s_score) as sum_score from score GROUP BY s_id ORDER BY sum_score DESC)a,
    (select @k:=0,@i:=0,@score:=0)s

    -- 21、查询不同老师所教不同课程平均分从高到低显示

    select a.t_id,c.t_name,a.c_id,ROUND(avg(s_score),2) as avg_score from course a
    left join score b on a.c_id=b.c_id
    left join teacher c on a.t_id=c.t_id
    GROUP BY a.c_id,a.t_id,c.t_name ORDER BY avg_score DESC;
    -- 22、查询所有课程的成绩第2名到第3名的学生信息及该课程成绩

    select d.*,c.排名,c.s_score,c.c_id from (
    select a.s_id,a.s_score,a.c_id,@i:=@i+1 as 排名 from score a,(select @i:=0)s where a.c_id='01'
    )c
    left join student d on c.s_id=d.s_id
    where 排名 BETWEEN 2 AND 3
    UNION
    select d.*,c.排名,c.s_score,c.c_id from (
    select a.s_id,a.s_score,a.c_id,@j:=@j+1 as 排名 from score a,(select @j:=0)s where a.c_id='02'
    )c
    left join student d on c.s_id=d.s_id
    where 排名 BETWEEN 2 AND 3
    UNION
    select d.*,c.排名,c.s_score,c.c_id from (
    select a.s_id,a.s_score,a.c_id,@k:=@k+1 as 排名 from score a,(select @k:=0)s where a.c_id='03'
    )c
    left join student d on c.s_id=d.s_id
    where 排名 BETWEEN 2 AND 3;


    -- 23、统计各科成绩各分数段人数:课程编号,课程名称,[100-85],[85-70],[70-60],[0-60]及所占百分比


    select distinct f.c_name,a.c_id,b.`85-100`,b.百分比,c.`70-85`,c.百分比,d.`60-70`,d.百分比,e.`0-60`,e.百分比 from score a
    left join (select c_id,SUM(case when s_score >85 and s_score <=100 then 1 else 0 end) as `85-100`,
    ROUND(100*(SUM(case when s_score >85 and s_score <=100 then 1 else 0 end)/count(*)),2) as 百分比
    from score GROUP BY c_id)b on a.c_id=b.c_id
    left join (select c_id,SUM(case when s_score >70 and s_score <=85 then 1 else 0 end) as `70-85`,
    ROUND(100*(SUM(case when s_score >70 and s_score <=85 then 1 else 0 end)/count(*)),2) as 百分比
    from score GROUP BY c_id)c on a.c_id=c.c_id
    left join (select c_id,SUM(case when s_score >60 and s_score <=70 then 1 else 0 end) as `60-70`,
    ROUND(100*(SUM(case when s_score >60 and s_score <=70 then 1 else 0 end)/count(*)),2) as 百分比
    from score GROUP BY c_id)d on a.c_id=d.c_id
    left join (select c_id,SUM(case when s_score >=0 and s_score <=60 then 1 else 0 end) as `0-60`,
    ROUND(100*(SUM(case when s_score >=0 and s_score <=60 then 1 else 0 end)/count(*)),2) as 百分比
    from score GROUP BY c_id)e on a.c_id=e.c_id
    left join course f on a.c_id = f.c_id

    -- 24、查询学生平均成绩及其名次

    select a.s_id,
    @i:=@i+1 as '不保留空缺排名',
    @k:=(case when @avg_score=a.avg_s then @k else @i end) as '保留空缺排名',
    @avg_score:=avg_s as '平均分'
    from (select s_id,ROUND(AVG(s_score),2) as avg_s from score GROUP BY s_id)a,(select @avg_score:=0,@i:=0,@k:=0)b;
    -- 25、查询各科成绩前三名的记录
    -- 1.选出b表比a表成绩大的所有组
    -- 2.选出比当前id成绩大的 小于三个的
    select a.s_id,a.c_id,a.s_score from score a
    left join score b on a.c_id = b.c_id and a.s_score<b.s_score
    group by a.s_id,a.c_id,a.s_score HAVING COUNT(b.s_id)<3
    ORDER BY a.c_id,a.s_score DESC

    -- 26、查询每门课程被选修的学生数

    select c_id,count(s_id) from score a GROUP BY c_id

    -- 27、查询出只有两门课程的全部学生的学号和姓名
    select s_id,s_name from student where s_id in(
    select s_id from score GROUP BY s_id HAVING COUNT(c_id)=2);

    -- 28、查询男生、女生人数
    select s_sex,COUNT(s_sex) as 人数 from student GROUP BY s_sex

    -- 29、查询名字中含有"风"字的学生信息

    select * from student where s_name like '%风%';

    -- 30、查询同名同性学生名单,并统计同名人数

    select a.s_name,a.s_sex,count(*) from student a JOIN
    student b on a.s_id !=b.s_id and a.s_name = b.s_name and a.s_sex = b.s_sex
    GROUP BY a.s_name,a.s_sex

    -- 31、查询1990年出生的学生名单

    select s_name from student where s_birth like '1990%'

    -- 32、查询每门课程的平均成绩,结果按平均成绩降序排列,平均成绩相同时,按课程编号升序排列

    select c_id,ROUND(AVG(s_score),2) as avg_score from score GROUP BY c_id ORDER BY avg_score DESC,c_id ASC

    -- 33、查询平均成绩大于等于85的所有学生的学号、姓名和平均成绩

    select a.s_id,b.s_name,ROUND(avg(a.s_score),2) as avg_score from score a
    left join student b on a.s_id=b.s_id GROUP BY s_id HAVING avg_score>=85

    -- 34、查询课程名称为"数学",且分数低于60的学生姓名和分数

    select a.s_name,b.s_score from score b LEFT JOIN student a on a.s_id=b.s_id where b.c_id=(
    select c_id from course where c_name ='数学') and b.s_score<60

    -- 35、查询所有学生的课程及分数情况;


    select a.s_id,a.s_name,
    SUM(case c.c_name when '语文' then b.s_score else 0 end) as '语文',
    SUM(case c.c_name when '数学' then b.s_score else 0 end) as '数学',
    SUM(case c.c_name when '英语' then b.s_score else 0 end) as '英语',
    SUM(b.s_score) as '总分'
    from student a left join score b on a.s_id = b.s_id
    left join course c on b.c_id = c.c_id
    GROUP BY a.s_id,a.s_name


    -- 36、查询任何一门课程成绩在70分以上的姓名、课程名称和分数;
    select a.s_name,b.c_name,c.s_score from course b left join score c on b.c_id = c.c_id
    left join student a on a.s_id=c.s_id where c.s_score>=70

    -- 37、查询不及格的课程
    select a.s_id,a.c_id,b.c_name,a.s_score from score a left join course b on a.c_id = b.c_id
    where a.s_score<60

    --38、查询课程编号为01且课程成绩在80分以上的学生的学号和姓名;
    select a.s_id,b.s_name from score a LEFT JOIN student b on a.s_id = b.s_id
    where a.c_id = '01' and a.s_score>80

    -- 39、求每门课程的学生人数
    select count(*) from score GROUP BY c_id;

    -- 40、查询选修"张三"老师所授课程的学生中,成绩最高的学生信息及其成绩


    -- 查询老师id
    select c_id from course c,teacher d where c.t_id=d.t_id and d.t_name='张三'
    -- 查询最高分(可能有相同分数)
    select MAX(s_score) from score where c_id='02'
    -- 查询信息
    select a.*,b.s_score,b.c_id,c.c_name from student a
    LEFT JOIN score b on a.s_id = b.s_id
    LEFT JOIN course c on b.c_id=c.c_id
    where b.c_id =(select c_id from course c,teacher d where c.t_id=d.t_id and d.t_name='张三')
    and b.s_score in (select MAX(s_score) from score where c_id='02')


    -- 41、查询不同课程成绩相同的学生的学生编号、课程编号、学生成绩
    select DISTINCT b.s_id,b.c_id,b.s_score from score a,score b where a.c_id != b.c_id and a.s_score = b.s_score


    -- 42、查询每门功成绩最好的前两名
    -- 牛逼的写法
    select a.s_id,a.c_id,a.s_score from score a
    where (select COUNT(1) from score b where b.c_id=a.c_id and b.s_score>=a.s_score)<=2 ORDER BY a.c_id


    -- 43、统计每门课程的学生选修人数(超过5人的课程才统计)。要求输出课程号和选修人数,查询结果按人数降序排列,若人数相同,按课程号升序排列
    select c_id,count(*) as total from score GROUP BY c_id HAVING total>5 ORDER BY total,c_id ASC

    -- 44、检索至少选修两门课程的学生学号
    select s_id,count(*) as sel from score GROUP BY s_id HAVING sel>=2

    -- 45、查询选修了全部课程的学生信息
    select * from student where s_id in(
    select s_id from score GROUP BY s_id HAVING count(*)=(select count(*) from course))


    --46、查询各学生的年龄
    -- 按照出生日期来算,当前月日 < 出生年月的月日则,年龄减一

    select s_birth,(DATE_FORMAT(NOW(),'%Y')-DATE_FORMAT(s_birth,'%Y') -
    (case when DATE_FORMAT(NOW(),'%m%d')>DATE_FORMAT(s_birth,'%m%d') then 0 else 1 end)) as age
    from student;


    -- 47、查询本周过生日的学生
    select * from student where WEEK(DATE_FORMAT(NOW(),'%Y%m%d'))=WEEK(s_birth)
    select * from student where YEARWEEK(s_birth)=YEARWEEK(DATE_FORMAT(NOW(),'%Y%m%d'))

    select WEEK(DATE_FORMAT(NOW(),'%Y%m%d'))

    -- 48、查询下周过生日的学生
    select * from student where WEEK(DATE_FORMAT(NOW(),'%Y%m%d'))+1 =WEEK(s_birth)

    -- 49、查询本月过生日的学生

    select * from student where MONTH(DATE_FORMAT(NOW(),'%Y%m%d')) =MONTH(s_birth)

    -- 50、查询下月过生日的学生
    select * from student where MONTH(DATE_FORMAT(NOW(),'%Y%m%d'))+1 =MONTH(s_birth)
    ---------------------
    作者:启明星的指引
    来源:CSDN
    原文:https://blog.csdn.net/fashion2014/article/details/78826299/
    版权声明:本文为博主原创文章,转载请附上博文链接!

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  • 原文地址:https://www.cnblogs.com/feiwenstyle/p/10386776.html
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