汇编函数的调用
1: #include "stdio.h"
2: int add(int a, int b)
3: {
00401020 push ebp
00401021 mov ebp,esp
00401023 sub esp,44h
00401026 push ebx
00401027 push esi
00401028 push edi
00401029 lea edi,[ebp-44h]
0040102C mov ecx,11h
00401031 mov eax,0CCCCCCCCh
00401036 rep stos dword ptr [edi]
4: int c;
5: c = a + b;
00401038 mov eax,dword ptr [ebp+8]
0040103B add eax,dword ptr [ebp+0Ch]
0040103E mov dword ptr [ebp-4],eax
6: return c;
00401041 mov eax,dword ptr [ebp-4]
7: }
00401044 pop edi
00401045 pop esi
00401046 pop ebx
00401047 mov esp,ebp
00401049 pop ebp
0040104A ret
8: int main()
9: {
00401060 push ebp
00401061 mov ebp,esp
00401063 sub esp,44h
00401066 push ebx
00401067 push esi
00401068 push edi
00401069 lea edi,[ebp-44h]
0040106C mov ecx,11h
00401071 mov eax,0CCCCCCCCh
00401076 rep stos dword ptr [edi]
10: int Result = add(123, 456);
00401078 push 1C8h
0040107D push 7Bh
0040107F call @ILT+0(add) (00401005)
00401084 add esp,8
00401087 mov dword ptr [ebp-4],eax
11: printf("\n************\n");
0040108A push offset string "\n************\n" (0042001c)
0040108F call printf (004010c0)
00401094 add esp,4
12: return 0;
00401097 xor eax,eax
13: }