Interlocked.Increment 方法 和Interlocked.Decrement 方法作用

Interlocked.Increment 方法：让++成为原子操作；Interlocked.Decrement 方法让--成为原子操作。
什么叫原子操作呢。就是不会被别人打断，因为C#中的一个语句，编译成机器代码后会变成多个语句。
在多线程环境中，线程切换有可能会发生在这多个语句中间。使用Interlocked.Increment,Interlocked.Decrement 可以避免被打断,保证线程安全。

使用Interlocked.Increment 方法和Interlocked.Decrement 方法MSND例子：

using System;
using System.Threading;
class Test
{
static void Main()
    {
        Thread thread1 = new Thread(new ThreadStart(ThreadMethod));
        Thread thread2 = new Thread(new ThreadStart(ThreadMethod));
        thread1.Start();
        thread2.Start();
        thread1.Join();
        thread2.Join();
// Have the garbage collector run the finalizer for each
// instance of CountClass and wait for it to finish.
        GC.Collect();
        GC.WaitForPendingFinalizers();
        Console.WriteLine("UnsafeInstanceCount: {0}" +
" SafeCountInstances: {1}",
            CountClass.UnsafeInstanceCount.ToString(),
            CountClass.SafeInstanceCount.ToString());
    }
static void ThreadMethod()
    {
        CountClass cClass;
// Create 100,000 instances of CountClass.
for(int i = 0; i < 100000; i++)
        {
            cClass = new CountClass();
        }
    }
}
class CountClass
{
static int unsafeInstanceCount = 0;//不使用原子操作
static int   safeInstanceCount = 0;//使用原子操作
static public int UnsafeInstanceCount
    {
get {return unsafeInstanceCount;}
    }
static public int SafeInstanceCount
    {
get {return safeInstanceCount;}
    }
public CountClass()
    {
        unsafeInstanceCount++;
        Interlocked.Increment(ref safeInstanceCount);
    }
    ~CountClass()
    {
        unsafeInstanceCount--;
        Interlocked.Decrement(ref safeInstanceCount);
    }
}

不用原子操作例子

class Program
    {
static void Main(string[] args)
        {
for (int loop = 0; loop < 20; loop++)
            {
                sum = 0;
                Thread t1 = new Thread(Thread1);
                Thread t2 = new Thread(Thread2);
                t1.Start();
                t2.Start();
                t1.Join();
                t2.Join();
                Console.WriteLine("sum = " + sum);         // sum = 200000 ?
            }
        }
static int sum;
static void Thread1()
        {
for (int i = 0; i < 100000; i++) sum++;
        }
static void Thread2()
        {
for (int i = 0; i < 100000; i++) sum++;
        }
    }
结果：

/*
sum = 200000
sum = 200000
sum = 200000
sum = 200000
sum = 200000
sum = 200000
sum = 200000
sum = 200000
sum = 192361
sum = 175155
sum = 200000
sum = 176024
sum = 200000
sum = 200000
sum = 200000
sum = 200000
sum = 200000
sum = 200000
sum = 200000
sum = 176322
*/
Why the sum is not always 200000?
The reason is that sum++ is not thread safe (see the possible problem).
That is the reason we need Interlocked.Increment(), which guarantees the sum is always 200000.

Thread1 (sum++)                   Thread2 (sum++)
--------------------------------------------------------------------
mov   EAX, dword ptr sum          .
inc   EAX                         .
.                                 mov   EAX, dword ptr sum           // load sum into a register
.                                 inc   EAX                          // increase it
.                                 mov   dword ptr sum, EAX           // save back
mov   dword ptr sum, EAX
--------------------------------------------------------------------
problem: two sum++ are called in different thread,
but the sum is incremented only once.
也就是说因为C#中的一个语句，编译成机器代码后会变成多个语句，线程不安全，sum++的第100次操作就被打断了，而在第200000次++操作结束后CPU才轮询到sum++的第100次操作，这时sum的值就是101，

 

转自: http://www.cnblogs.com/cappuccino/archive/2011/01/06/1927659.html