zoukankan      html  css  js  c++  java
  • leetcode 数据库题解

    184. Department Highest Salary

    题意:

    The Employee table holds all employees. Every employee has an Id, a salary, and there is also a column for the department Id.
    
    +----+-------+--------+--------------+
    | Id | Name  | Salary | DepartmentId |
    +----+-------+--------+--------------+
    | 1  | Joe   | 70000  | 1            |
    | 2  | Henry | 80000  | 2            |
    | 3  | Sam   | 60000  | 2            |
    | 4  | Max   | 90000  | 1            |
    +----+-------+--------+--------------+
    The Department table holds all departments of the company.
    
    +----+----------+
    | Id | Name     |
    +----+----------+
    | 1  | IT       |
    | 2  | Sales    |
    +----+----------+
    Write a SQL query to find employees who have the highest salary in each of the departments. For the above tables, Max has the highest salary in the IT department and Henry has the highest salary in the Sales department.
    
    +------------+----------+--------+
    | Department | Employee | Salary |
    +------------+----------+--------+
    | IT         | Max      | 90000  |
    | Sales      | Henry    | 80000  |
    +------------+----------+--------+
    View Code

    解法:

    1 select d.Name as Department, e.Name as Employee, e.Salary from Employee as e ,(select DepartmentId, max(Salary) max from Employee group by DepartmentId) t,Department as d where e.Salary = t.max and e.DepartmentId = t.DepartmentId and d.Id = e.DepartmentId;

    176. Second Highest Salary

    题意:

    Write a SQL query to get the second highest salary from the Employee table.
    
    +----+--------+
    | Id | Salary |
    +----+--------+
    | 1  | 100    |
    | 2  | 200    |
    | 3  | 300    |
    +----+--------+
    For example, given the above Employee table, the second highest salary is 200. If there is no second highest salary, then the query should return null.
    View Code

    解法:Using max() will return a NULL if the value doesn't exist. So there is no need to UNION a NULL. Of course, if the second highest value is guaranteed to exist, using LIMIT 1,1 will be the best answer.

    1 select max(Salary) as SecondHighestSalary from Employee where Salary < (select max(Salary) from Employee);

    197. Rising Temperature

    题意:

    Given a Weather table, write a SQL query to find all dates' Ids with higher temperature compared to its previous (yesterday's) dates.
    
    +---------+------------+------------------+
    | Id(INT) | Date(DATE) | Temperature(INT) |
    +---------+------------+------------------+
    |       1 | 2015-01-01 |               10 |
    |       2 | 2015-01-02 |               25 |
    |       3 | 2015-01-03 |               20 |
    |       4 | 2015-01-04 |               30 |
    +---------+------------+------------------+
    For example, return the following Ids for the above Weather table:
    +----+
    | Id |
    +----+
    |  2 |
    |  4 |
    +----+
    Subscribe to see which companies asked this question.
    View Code

    解法:

    1 select a.Id as Id from Weather a, Weather b where to_days(a.Date)-to_days(b.Date) = 1 and a.Temperature > b.Temperature;
  • 相关阅读:
    hadoop 3.0.0 alpha3 安装、配置
    集群使用初步
    转 mysql 中sql 语句查询今天、昨天、7天、近30天、本月、上一月 数据
    java 内存溢出
    获取手机上安装的应用信息
    使apk具有system权限
    Android基础之sqlite 数据库简单操作
    转 Android:文件下载和写入SD卡学习小结
    Android判断Service是否运行
    Android 定时重复启动弹出窗口。
  • 原文地址:https://www.cnblogs.com/fisherinbox/p/6716600.html
Copyright © 2011-2022 走看看