xcode下编译报错：ISO C++ forbids declaration of 'iterator' with no type
出错点：
template<class T>
class MyVector: public std::vector<T>
{
public:
typedef std::vector<T> vecType;
typedef vecType::iterator vecIterator; //报错
MyVector(){};
MyVector(const vecType& _vec);
//.......
//.......
};
根据别人的回答，http://stackoverflow.com/questions/1732895/error-iso-c-forbids-declaration-of-iterator-with-no-type。找到原因：
“The reason being being that iterator is dependent on what T is, so the compiler can't be sure it's a typename unless you tell it.”
加 typename，修改后编译通过：
template<class T>
class MyVector: public std::vector<T>
{
public:
typedef std::vector<T> vecType;
typedef typename vecType::iterator vecIterator; //typename
MyVector(){};
MyVector(const vecType& _vec);
//.......
//.......
};
mark! 还有一点“C++编译器不能支持对模板的分离式编译”，why? google.....