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  • LeetCode 125. Valid Palindrome

    分析

    难度 易

    来源

    https://leetcode.com/problems/valid-palindrome/

    题目

    Given a string, determine if it is a palindrome, considering only alphanumeric characters and ignoring cases.

    Note: For the purpose of this problem, we define empty string as valid palindrome.

    Example 1:

    Input: "A man, a plan, a canal: Panama"
    Output: true

    Example 2:

    Input: "race a car"
    Output: false

    解答

    Runtime: 6 ms, faster than 72.53% of Java online submissions for Valid Palindrome.

     1 package LeetCode;
     2 
     3 public class L125_ValidPalindrome {
     4     public boolean isPalindrome(String s) {
     5         s=s.toLowerCase();
     6         if(s.length()<=1)
     7             return true;
     8         int head=0,tail=s.length()-1;
     9         while(head<=tail){
    10             if(!Character.isLetterOrDigit(s.charAt(head)))
    11             {
    12                 head++;
    13                 continue;
    14             }
    15             if(!Character.isLetterOrDigit(s.charAt(tail)))
    16             {
    17                 tail--;
    18                 continue;
    19             }
    20             if(s.charAt(head)==s.charAt(tail))
    21             {
    22                 head++;
    23                 tail--;
    24             }else
    25                 return false;
    26         }
    27         return true;
    28     }
    29     public static void main(String[] args){
    30         L125_ValidPalindrome l125=new L125_ValidPalindrome();
    31         String s="A man, a plan, a canal: Panama";
    32         //String s="race a car";
    33         System.out.println(l125.isPalindrome(s));
    34     }
    35 }

     

    博客园的编辑器没有CSDN的编辑器高大上啊
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  • 原文地址:https://www.cnblogs.com/flowingfog/p/9913647.html
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