题目
Given a binary tree, you need to compute the length of the diameter of the tree. The diameter of a binary tree is the length of the longest path between any two nodes in a tree. This path may or may not pass through the root.
Example:
Given a binary tree
1
/
2 3
/
4 5
Return 3, which is the length of the path [4,2,1,3] or [5,2,1,3].
Note: The length of path between two nodes is represented by the number of edges between them.
简洁代码
public int diameterOfBinaryTree(TreeNode root) {
if(root == null) return 0;
//左右子树的深度之和
int diameter = getDepth(root.left) + getDepth(root.right);
//返回左子树、右子树、左右子树的深度之和中的最大值
return Math.max(diameter,Math.max(diameterOfBinaryTree(root.left),diameterOfBinaryTree(root.right)));
}
//求树的深度
public int getDepth(TreeNode root){
if(root == null) return 0;
return Math.max(getDepth(root.left),getDepth(root.right)) + 1;
}
过程分析
public class TreeDiemiter {
static class TreeNode{
TreeNode left = null;
TreeNode right = null;
int val = 0;
public TreeNode(int val) {
this.val = val;
}
}
public int diameterOfBinaryTree(TreeNode root) {
if(root == null) return 0;
//左右子树的深度之和
int diameter = getDepth(root.left) + getDepth(root.right);
//返回左子树、右子树、左右子树的深度之和中的最大值
return Math.max(diameter,Math.max(diameterOfBinaryTree(root.left),diameterOfBinaryTree(root.right)));
}
//求树的深度
public int getDepth(TreeNode root){
if(root == null) return 0;
return Math.max(getDepth(root.left),getDepth(root.right)) + 1;
}
/*另外一种写法求树的深度
public int TreeDepth(TreeNode root) {
if(root == null) return 0;
int leftDepth = TreeDepth(root.left);
int rightDepth = TreeDepth(root.right);
return leftDepth > rightDepth? leftDepth + 1:rightDepth + 1;//这里要加1的原因是深度数的是节点的个数
}*/
public static void main(String[] args){
TreeDiemiter.TreeNode treeNode = new TreeDiemiter.TreeNode(1);
treeNode.left = new TreeDiemiter.TreeNode(2);
treeNode.right = new TreeDiemiter.TreeNode(3);
treeNode.left.left = new TreeDiemiter.TreeNode(4);
treeNode.left.right = new TreeDiemiter.TreeNode(5);
TreeDiemiter treeDiemiter = new TreeDiemiter();
int res = treeDiemiter.diameterOfBinaryTree(treeNode);
System.out.println(res);
}
}
public class TreeDiemiter {
static class TreeNode{
TreeNode left = null;
TreeNode right = null;
int val = 0;
public TreeNode(int val) {
this.val = val;
}
}
public int diameterOfBinaryTree(TreeNode root) {
System.out.println("=====================");
if(root == null) return 0;
//左右子树的深度之和
int leftDepth = getDepth(root.left);
System.out.println("leftDepth:" + leftDepth);
int rightDepth = getDepth(root.right);
System.out.println("rightDepth:" + rightDepth);
int diameter = leftDepth + rightDepth;
System.out.println("diameter:" + diameter);
//返回左子树、右子树、左右子树的深度之和中的最大值
return Math.max(diameter,Math.max(diameterOfBinaryTree(root.left),diameterOfBinaryTree(root.right)));
}
//求树的深度
public int getDepth(TreeNode root){
if(root == null) return 0;
return Math.max(getDepth(root.left),getDepth(root.right)) + 1;
}
public static void main(String[] args){
TreeDiemiter.TreeNode treeNode = new TreeDiemiter.TreeNode(1);
treeNode.left = new TreeDiemiter.TreeNode(2);
treeNode.right = new TreeDiemiter.TreeNode(3);
treeNode.left.left = new TreeDiemiter.TreeNode(4);
treeNode.left.right = new TreeDiemiter.TreeNode(5);
TreeDiemiter treeDiemiter = new TreeDiemiter();
int res = treeDiemiter.diameterOfBinaryTree(treeNode);
System.out.println(res);
}
}
=====================
leftDepth:2
rightDepth:1
diameter:3
=====================
leftDepth:1
rightDepth:1
diameter:2
=====================
leftDepth:0
rightDepth:0
diameter:0
=====================
=====================
=====================
leftDepth:0
rightDepth:0
diameter:0
=====================
=====================
=====================
leftDepth:0
rightDepth:0
diameter:0
=====================
=====================
3
Process finished with exit code 0