C语言实现统计字符个数

#include<stdio.h>

int main()

{

    int sz[10]={0},zm[26]={0},z[26]={0},i,space=0,e=0,t=0;

    char c;

    printf("请输入一段字符，统计其中各字符的数量 ");

    while((c=getchar())!=' ')

    {

        if(c<='z'&&c>='a')

            zm[c-'a']++;

        else if(c<='Z'&&c>='A')

            z[c-'A']++;

        else if(c<='9'&&c>='0')

            sz[c-'0']++;

        else if(c==' ')

            space++;

        else

            e++;

    }

    printf(" ");

    for(i=0;i<=9;i++)

    {

        t++;

        printf(" %d的个数为%d   ",i,sz[i]);

        if(t%3==0)

            printf(" ");

    }

    t=0;

    printf(" ");

    for(i=0;i<=25;i++)

    {

        t++;

        printf(" %c的个数为%d   ",i+97,zm[i]);

        if(t%3==0)

            printf(" ");

    }

    t=0;

    printf(" ");

    for(i=0;i<=25;i++)

    {

        t++;

        printf(" %c的个数为%d   ",i+65,z[i]);

        if(t%3==0)

            printf(" ");

    }

    t=0;

    printf(" ");

    printf(" 空格的个数为%d ",space);

    printf(" 其他字符的个数为%d ",e);

    return 0;

}