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  • 如何在tomcat启动的时候运行一个Java类

    设置个Listener就好了,在web.xml中指定描述。

    web.xml其实就是tomcat启动的时候会读取的一个描述文件,比如访问服务器的时候首页等都可以在里面指定,有相应的tag。这里有解释:http://blog.chinaunix.net/uid-20399471-id-1687965.html

    实现这个Listener的接口:

     1 public class MyServletContextListener implements ServletContextListener {
     2 
     3   @Override
     4   public void contextDestroyed(ServletContextEvent arg0) {
     5     //Notification that the servlet context is about to be shut down.   
     6   }
     7 
     8   @Override
     9   public void contextInitialized(ServletContextEvent arg0) {
    10     // do all the tasks that you need to perform just after the server starts
    11 
    12     //Notification that the web application initialization process is starting
    13   }
    14 
    15 }

    然后在web.xml中编写listener的标签,添加listener类:

    MyTestListener换成自己实现ServletContextListener接口的类名
    <listener>
         <listener-class>[package].MyTestListener</listener-class>
        </listener>
      

    references:

    http://stackoverflow.com/questions/13819773/how-to-run-specific-java-code-on-tomcat-start-or-on-application-deploy

    http://stackoverflow.com/questions/158336/is-there-a-way-to-run-a-method-class-only-on-tomcat-startup

    http://crunchify.com/how-to-run-java-program-automatically-on-tomcat-startup/

    http://blog.sina.com.cn/s/blog_6ea90e4b0100ny3t.html

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  • 原文地址:https://www.cnblogs.com/foohack/p/5033608.html
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