In a party held by CocaCola company, several students stand in a circle and play a game.
One of them is selected as the first, and should say the number 1. Then they continue to count number from 1 one by one (clockwise). The game is interesting in that, once someone counts a number which is a multiple of 7 (e.g. 7, 14, 28, ...) or contains the digit '7' (e.g. 7, 17, 27, ...), he shall say "CocaCola" instead of the number itself.
For example, 4 students play this game. At some time, the first one says 25, then the second should say 26. The third should say "CocaCola" because 27 contains the digit '7'. The fourth one should say "CocaCola" too, because 28 is a multiple of 7. Then the first one says 29, and the game goes on. When someone makes a mistake, the game ends.
During a game, you may hear a consecutive of p "CocaCola"s. So what is the minimum number that can make this situation happen?
For example p = 2, that means there are a consecutive of 2 "CocaCola"s. This situation happens in 27-28 as stated above. 27 is then the minimum number to make this situation happen.
Input
Standard input will contain multiple test cases. The first line of the input is a single integer T (1 <= T <= 100) which is the number of test cases. And it will be followed by T consecutive test cases.
There is only one line for each case. The line contains only one integer p (1 <= p <= 99).
Output
Results should be directed to standard output. The output of each test case should be a single integer in one line, which is the minimum possible number for the first of the p "CocaCola"s stands for.
Sample Input
2 2 3
Sample Output
27 70
Author: HANG, Hang
Source: The 5th Zhejiang Provincial Collegiate Programming Contest
//1786694 2009-03-12 19:23:31 Wrong Answer 2965 C++ 0 184 吴
//1786732 2009-03-12 19:48:24 Accepted 2965 C++ 0 184 吴
////ZOJ 2695 Accurately Say "CocaCola"! 简单规律题 08年浙江省大学生程序设计竞赛
#include <iostream>
using namespace std;
int a[100];
int main()
{
int i;
a[1]=7;
a[2]=27;
for(i=3;i<=10;i++)
a[i]=70;
a[11]=270; //第一次因为a[11]=469错误一次
for(i=12;i<=99;i++)
a[i]=700;
int test;
scanf("%d",&test);
while(test--)
{
int n;
scanf("%d",&n);
printf("%d\n",a[n]);
}
return 0;
}