Time Limit: 0.5 Seconds Memory Limit: 65536K
Total Runs: 348 Accepted Runs: 200
The magician shuffles a small pack of cards, holds it face down and performs the following procedure:
- The top card is moved to the bottom of the pack. The new top card is dealt face up onto the table. It is the Ace of Spades.
- Two cards are moved one at a time from the top to the bottom. The next card is dealt face up onto the table. It is the Two of Spades.
- Three cards are moved one at a time ...
- This goes on until the nth and last card turns out to be the n of Spades.
This impressive trick works if the magician knows how to arrange the cards beforehand (and knows how to give a false shuffle). Your program has to determine the initial order of the cards for a given number of cards, 1 ≤ n ≤ 13.
Input specifications
On the first line of the input is a single positive integer, telling the number of test cases to follow. Each case consists of one line containing the integer n.
Output specifications
For each test case, output a line with the correct permutation of the values 1 to n, space separated. The first number showing the top card of the pack, etc ...
Sample input
2 4 5
Output for sample input
2 1 4 3 3 1 4 5 2
Source: Nordic Collegiate Contest 2006
#include <iostream>
#include <string>
using namespace std;
string str[14];
int t,n;
int main()
{
cin>>t;
str[1]="1";
str[2]="2 1";
str[3]="3 1 2";
str[4]="2 1 4 3";
str[5]="3 1 4 5 2";
str[6]="4 1 6 3 2 5";
str[7]="5 1 3 4 2 6 7";
str[8]="3 1 7 5 2 6 8 4";
str[9]="7 1 8 6 2 9 4 5 3";
str[10]="9 1 8 5 2 4 7 6 3 10";
str[11]="5 1 6 4 2 10 11 7 3 8 9";
str[12]="7 1 4 9 2 11 10 8 3 6 5 12";
str[13]="4 1 13 11 2 10 6 7 3 5 12 9 8";
while(t--)
{
cin>>n;
cout<<str[n]<<endl;
}
return 0;
}
#include <string>
using namespace std;
string str[14];
int t,n;
int main()
{
cin>>t;
str[1]="1";
str[2]="2 1";
str[3]="3 1 2";
str[4]="2 1 4 3";
str[5]="3 1 4 5 2";
str[6]="4 1 6 3 2 5";
str[7]="5 1 3 4 2 6 7";
str[8]="3 1 7 5 2 6 8 4";
str[9]="7 1 8 6 2 9 4 5 3";
str[10]="9 1 8 5 2 4 7 6 3 10";
str[11]="5 1 6 4 2 10 11 7 3 8 9";
str[12]="7 1 4 9 2 11 10 8 3 6 5 12";
str[13]="4 1 13 11 2 10 6 7 3 5 12 9 8";
while(t--)
{
cin>>n;
cout<<str[n]<<endl;
}
return 0;
}