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  • lingo旅行商问题代码

    旅行商问题:
    MODEL:
    sets:
    cities/1..10/:level; !level(i)= the level of city;
    link(cities, cities):
    distance, !The distance matrix;
    x; ! x(i,j)=1 if we use link i,j;
    endsets
    data: !Distance matrix, it need not be symmetirc;
    distance = 0 8 5 9 12 14 12 16 17 22
    8 0 9 15 16 8 11 18 14 22
    5 9 0 7 9 11 7 12 12 17
    9 15 7 0 3 17 10 7 15 15
    12 16 9 3 0 8 10 6 15 15
    14 8 11 17 8 0 9 14 8 16
    12 11 7 10 10 9 0 8 6 11
    16 18 12 7 6 14 8 0 11 11
    17 14 12 15 15 8 6 11 0 10
    22 22 17 15 15 16 11 11 10 0;
    enddata
    n=@size(cities); !The model size;
    ! Minimize total distance of the links;
    min=@sum(link(i,j)|i #ne# j: distance(i,j)*x(i,j));
    !For city i;
    @for(cities(i) :
    ! It must be entered;
    @sum(cities(j)| j #ne# i: x(j,i))=1;
    ! It must be departed;
    @sum(cities(j)| j #ne# i: x(i,j))=1;
    ! level(j)=levle(i)+1, if we link j and i;
    @for(cities(j)| j #gt# 1 #and# j #ne# i :
    level(j) >= level(i) + x(i,j)
    - (n-2)*(1-x(i,j)) + (n-3)*x(j,i);
    );
    );
    ! Make the x's 0/1;
    @for(link : @bin(x));
    ! For the first and last stop;
    @for(cities(i) | i #gt# 1 :
    level(i)<=n-1-(n-2)*x(1,i);
    level(i)>=1+(n-2)*x(i,1);
    );
    END

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  • 原文地址:https://www.cnblogs.com/francischeng/p/9437809.html
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