leetcode_705

Design a HashSet without using any built-in hash table libraries.

To be specific, your design should include these functions:

• add(value): Insert a value into the HashSet. 
• contains(value) : Return whether the value exists in the HashSet or not.
• remove(value): Remove a value in the HashSet. If the value does not exist in the HashSet, do nothing.

Example:

MyHashSet hashSet = new MyHashSet();
hashSet.add(1);         
hashSet.add(2);         
hashSet.contains(1);    // returns true
hashSet.contains(3);    // returns false (not found)
hashSet.add(2);          
hashSet.contains(2);    // returns true
hashSet.remove(2);          
hashSet.contains(2);    // returns false (already removed)

Note:

• All values will be in the range of [0, 1000000].
• The number of operations will be in the range of [1, 10000].
• Please do not use the built-in HashSet library.

Solution1:

获得的经验

1 。 remove(self, value)参数是value 2   pop(self, index=None)参数是index

2. hashset hash是没有重复的元素的因为要hash

class MyHashSet(object):

    def __init__(self):
        """
        Initialize your data structure here.
        """
        self.list = []

    def add(self, key):
        """
        :type key: int
        :rtype: void
        """
        if key not in self.list:
            self.list.append(key)
    def remove(self, key):
        """
        :type key: int
        :rtype: void
        """
        if key in self.list:
            self.list.remove(key)

    def contains(self, key):
        """
        Returns true if this set contains the specified element
        :type key: int
        :rtype: bool
        """
        return key in self.list

# Your MyHashSet object will be instantiated and called as such:
# obj = MyHashSet()
# obj.add(key)
# obj.remove(key)
# param_3 = obj.contains(key)