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  • for语句之打印三角形问题

    1.左下角直角三角形

    Console.Write("请输入要打印几行:");
                int a = Convert.ToInt32(Console.ReadLine());
    
                for (int i = 1; i <= a; i++)
                {
                    for (int j = 1; j <= i; j++)
                    {
                        Console.Write("");
                    }
                    Console.WriteLine();
                }

    2.左上角直角三角形

    Console.Write("请输入要打印几行:");
                int a = Convert.ToInt32(Console.ReadLine());
    
                for (int i = 1; i <= a; i++)
                {
                    for (int j = a - i; j >= 0; j--)
                    {
                        Console.Write("");
                    }
    
                    Console.WriteLine();
                }

    3.右下角直角三角形

     Console.Write("请输入要打印几行:");
                int a = Convert.ToInt32(Console.ReadLine());
    
                for (int i = 0; i < a; i++)
                {
                    for (int j = 1; j <= a - (i + 1); j++)
                    {
                        Console.Write("  ");
                    }
                    for (int k = 1; k <= i + 1; k++)
                    {
                        Console.Write("");
                    }
                    Console.WriteLine();
                }

    4.菱形

     Console.Write("请输入要打印几行:");
                int a = Convert.ToInt32(Console.ReadLine());
    
                for (int i = 1; i <= a; i++)
                {
                    for (int k = 1; k <= a-i; k++)
                    {
                        Console.Write("  ");
                    }
                    for (int x = 1; x <= i*2-1; x++)
                    {
                        Console.Write("");
                    }
                    Console.WriteLine();
                }
                for (int j = 1; j < a; j++)
                {
                    for (int k2 = 1; k2 <= j; k2++)
                    {
                        Console.Write("  ");
                    }
                    for (int x2 = 1; x2 <= (a-j)*2-1; x2++)
                    {
                        Console.Write("");
                    }
                    Console.WriteLine();
                }

     

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  • 原文地址:https://www.cnblogs.com/franky2015/p/4631609.html
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