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  • SQL11

     题目描述
    获取所有非manager员工当前的薪水情况,给出dept_no、emp_no以及salary ,当前表示to_date='9999-01-01'

        CREATE TABLE `dept_emp` (
        `emp_no` int(11) NOT NULL,
        `dept_no` char(4) NOT NULL,
        `from_date` date NOT NULL,
        `to_date` date NOT NULL,
        PRIMARY KEY (`emp_no`,`dept_no`));
        CREATE TABLE `dept_manager` (
        `dept_no` char(4) NOT NULL,
        `emp_no` int(11) NOT NULL,
        `from_date` date NOT NULL,
        `to_date` date NOT NULL,
        PRIMARY KEY (`emp_no`,`dept_no`));
        CREATE TABLE `employees` (
        `emp_no` int(11) NOT NULL,
        `birth_date` date NOT NULL,
        `first_name` varchar(14) NOT NULL,
        `last_name` varchar(16) NOT NULL,
        `gender` char(1) NOT NULL,
        `hire_date` date NOT NULL,
        PRIMARY KEY (`emp_no`));
        CREATE TABLE `salaries` (
        `emp_no` int(11) NOT NULL,
        `salary` int(11) NOT NULL,
        `from_date` date NOT NULL,
        `to_date` date NOT NULL,
        PRIMARY KEY (`emp_no`,`from_date`));

    示例:
    dept_no    | emp_no|salary

    d001    |10001  | 88958

    d004    |10003  | 43311

    解答思路:
    先查出所有员工的工资情况,再排除掉非manager员工的记录

            1.select salary from salaries s left join dept_emp de on s.emp_no=de.emp_no where 
        s.to_date='9999-01-01'

        
            2.select de.dept_no,de.emp_no from dept_emp de left join dept_manager dr on 
        de.emp_no=dr.emp_no  where de.to_date='9999-01-01' and dr.emp_no is null

    故答案为:

        select de.dept_no,de.emp_no,
        (select salary from salaries where 
         emp_no=de.emp_no and to_date='9999-01-01') as salary 
        from dept_emp de left join dept_manager dm 
        on de.emp_no=dm.emp_no  where de.to_date='9999-01-01' and dm.emp_no is null;

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  • 原文地址:https://www.cnblogs.com/fruit1024/p/12294098.html
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