编写一个程序，求s=1+(1+2)+(1+2+3)+…+(1+2+3+…+n)的值
1 #import <Foundation/Foundation.h>
2
3 int main(int argc, const char * argv[]) {
4 @autoreleasepool {
5 int shu=0,he=0;
6 for (int i=1; i<=100; i++) {
7 shu+=i;
8 he+=shu;
9 //printf("he is:%d ",he);
10 }
11 printf("he is:%d ",he);
12 return 0;
13 }
14 }
3 int main(int argc, const char * argv[]) {
4 @autoreleasepool {
5 int shu=0,he=0;
6 for (int i=1; i<=100; i++) {
7 shu+=i;
8 he+=shu;
9 //printf("he is:%d ",he);
10 }
11 printf("he is:%d ",he);
12 return 0;
13 }
14 }
执行结果：