zoukankan      html  css  js  c++  java
  • [暴力搜索] POJ 3087 Shuffle'm Up

    Shuffle'm Up
    Time Limit: 1000MS   Memory Limit: 65536K
    Total Submissions: 10003   Accepted: 4631

    Description

    A common pastime for poker players at a poker table is to shuffle stacks of chips. Shuffling chips is performed by starting with two stacks of poker chips, S1 and S2, each stack containing C chips. Each stack may contain chips of several different colors.

    The actual shuffle operation is performed by interleaving a chip from S1 with a chip from S2 as shown below for C = 5:

    The single resultant stack, S12, contains 2 * C chips. The bottommost chip of S12 is the bottommost chip from S2. On top of that chip, is the bottommost chip from S1. The interleaving process continues taking the 2nd chip from the bottom of S2 and placing that on S12, followed by the 2nd chip from the bottom of S1 and so on until the topmost chip from S1 is placed on top of S12.

    After the shuffle operation, S12 is split into 2 new stacks by taking the bottommost C chips from S12 to form a new S1 and the topmost C chips from S12 to form a new S2. The shuffle operation may then be repeated to form a new S12.

    For this problem, you will write a program to determine if a particular resultant stack S12 can be formed by shuffling two stacks some number of times.

    Input

    The first line of input contains a single integer N, (1 ≤ N ≤ 1000) which is the number of datasets that follow.

    Each dataset consists of four lines of input. The first line of a dataset specifies an integer C, (1 ≤ C ≤ 100) which is the number of chips in each initial stack (S1 and S2). The second line of each dataset specifies the colors of each of the C chips in stack S1, starting with the bottommost chip. The third line of each dataset specifies the colors of each of the C chips in stack S2 starting with the bottommost chip. Colors are expressed as a single uppercase letter (A through H). There are no blanks or separators between the chip colors. The fourth line of each dataset contains 2 * C uppercase letters (A through H), representing the colors of the desired result of the shuffling of S1 and S2 zero or more times. The bottommost chip’s color is specified first.

    Output

    Output for each dataset consists of a single line that displays the dataset number (1 though N), a space, and an integer value which is the minimum number of shuffle operations required to get the desired resultant stack. If the desired result can not be reached using the input for the dataset, display the value negative 1 (−1) for the number of shuffle operations.

    Sample Input

    2
    4
    AHAH
    HAHA
    HHAAAAHH
    3
    CDE
    CDE
    EEDDCC

    Sample Output

    1 2
    2 -1

    Source

     
    原题大意:每次洗牌,s2的最底下的放s12最底下,再往上放s1最底下的排。题目给的顺序也是最底下。
    解题思路:照着打,暴力也能0s。
     
    #include<stdio.h>
    #include<string.h>
    int main()
      {
      	 int T,n,times,i,j,cnt,flag;
    	 char s1[210],s2[210],s12[210],aim[210],temp[210];
      	 scanf("%d",&T);
      	 for(j=1;j<=T;++j)
      	   {
      	   	  cnt=flag=0;times=1;
      	   	  scanf("%d%s%s%s",&n,s1,s2,aim);
      	   	  for(i=0;i<strlen(s2);++i) s12[i*2]=s2[i];
      	   	  for(i=0;i<strlen(s1);++i) s12[i*2+1]=s1[i];
      	   	  s12[2*n]='';strcpy(temp,s12);
      	   	  while(strcmp(s12,aim)!=0)
      	   	    {
      	   	      strncpy(s1,s12,n);strncpy(s2,s12+n,n);
      	   	      for(i=0;i<strlen(s2);++i) s12[i*2]=s2[i];
      	   	      for(i=0;i<strlen(s1);++i) s12[i*2+1]=s1[i];
      	   	      s12[2*n]='';
      	   	      if(!strcmp(temp,s12)) 
    				{
    				   flag=1;
    				   break;
    			    }
      	   	      ++times;
    			}
    		  if(!flag) printf("%d %d
    ",j,times); else printf("%d -1
    ",j);
    	   }
      	 return 0;
      }
    

      

  • 相关阅读:
    c++基类和派生类的框架
    从文件读入7个数并排序
    字符串复制函数-简单
    c++函数模板-简单
    用初始化列表解决常私有变量问题-简单
    分配和释放内存-简单
    结构体小程序-简单
    转化的力量
    初次创业需要注意的几点
    重生的2014下半年的起点
  • 原文地址:https://www.cnblogs.com/fuermowei-sw/p/6216057.html
Copyright © 2011-2022 走看看