List<Map<String, Object>> 中根据某一个属性进行排序

//key 是要排序的属性，low1是要list排序的起始位置，high1是list的终止位置
private static List<Map<String, Object>> sortList(List<Map<String, Object>> list,String key, int low1, int high1){
int low = low1;
int high = high1;
String value = list.get(low).get(key).toString();
value = value.substring(0, value.length() - 1);
double x = Double.valueOf(value);
Map<String,Object> temp = list.get(low);
if(low1<high1){
while(low<high){
while(low<high && Double.valueOf(list.get(high).get(key).toString().substring(0, list.get(high).get(key).toString().length() -1))<=x){
high--;
}
list.set(low, list.get(high));
while(low < high && Double.valueOf(list.get(low).get(key).toString().substring(0, list.get(low).get(key).toString().length()-1))>=x){
low++;
}
list.set(high, list.get(low));
}
list.set(low, temp);
if(low>low1) sortList(list,key,low1,low-1);
if(high<high1) sortList(list,key,low+1,high1);
}
return list;
}

ps：本例子中list要排序的属性名字："AnjianSera" ,属性值带有%的，所以要截取String，再转化成Double类型进行比较；

      程序中是倒叙排序（desc），如果要想是正序排序（asc）,

while(low<high && Double.valueOf(list.get(high).get(key).toString().substring(0, list.get(high).get(key).toString().length() -1))<=x)

while(low < high && Double.valueOf(list.get(low).get(key).toString().substring(0, list.get(low).get(key).toString().length()-1))>=x)

两句代码的最后的<= 和 >= ，修改成>=和<= 即可