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  • python 由递归的dict构建树的画图代码

    createPlot(mytree)方法实现。

    其中myTree是一个字典,调用retrieveTree(0)可以获得一个字典的样式。

    Last login: Thu Feb 23 19:07:53 on ttys000
    B000000060143:~ zhanghao44$ ls
    4        Desktop        IdeaProjects    Music        PycharmProjects
    4a        Documents    Library        Pictures
    CLionProjects    Downloads    Movies        Public
    B000000060143:~ zhanghao44$ cd Desktop/
    B000000060143:Desktop zhanghao44$ ls
    help
    machinelearninginaction
    ps-dsp
    终端
    备份 
    屏幕快照 2017-02-22 下午7.36.56.png
    屏幕快照 2017-02-22 下午7.41.27.png
    屏幕快照 2017-02-22 下午7.45.55.png
    张浩出勤统计.xlsx
    B000000060143:Desktop zhanghao44$ cd machinelearninginaction/
    B000000060143:machinelearninginaction zhanghao44$ ls
    Ch02        Ch05        Ch08        Ch11        Ch14
    Ch03        Ch06        Ch09        Ch12        Ch15
    Ch04        Ch07        Ch10        Ch13        README.rst
    B000000060143:machinelearninginaction zhanghao44$ cd Ch03
    B000000060143:Ch03 zhanghao44$ ls
    classifierStorage.txt    treePlotter.py        trees.py
    lenses.txt        treePlotter.pyc        trees.pyc
    B000000060143:Ch03 zhanghao44$ vi trees.py
    B000000060143:Ch03 zhanghao44$ vi treePlotter.py
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    
    B000000060143:Ch03 zhanghao44$ vi treePlotter.py
    
        plotTree.totalD = float(getTreeDepth(inTree))
        plotTree.xOff = -0.5/plotTree.totalW; plotTree.yOff = 1.0;
        plotTree(inTree, (0.5,1.0), '')
        plt.show()
    
    def createPlot1():
        fig = plt.figure(1, facecolor='white')
        fig.clf()
        createPlot.ax1 = plt.subplot(111, frameon=False) #ticks for demo puropses
        plotNode('a decision node', (0.5, 0.1), (0.1, 0.5), decisionNode)
        plotNode('a leaf node', (0.8, 0.1), (0.3, 0.8), leafNode)
        plt.show()
    
    def retrieveTree(i):
        listOfTrees =[{'no surfacing': {0: 'no', 1: {'flippers': {0: 'no', 1: 'yes'}}}},
                      {'no surfacing': {0: 'no', 1: {'flippers': {0: {'head': {0: 'no', 1: 'yes'}}, 1: 'no'}}}}
                      ]
        return listOfTrees[i]
    
    #createPlot(thisTree)
    View Code
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  • 原文地址:https://www.cnblogs.com/futurehau/p/6435367.html
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