zoukankan      html  css  js  c++  java
  • bzoj4842 [Neerc2016]Delight for a Cat

    传送门:http://www.lydsy.com/JudgeOnline/problem.php?id=4842

    【题解】

    同 http://www.cnblogs.com/galaxies/p/20170627_c.html

    输出一个方案就行了

    # include <queue>
    # include <stdio.h>
    # include <string.h>
    # include <iostream>
    # include <algorithm>
    
    using namespace std;
    
    typedef long long ll;
    typedef unsigned long long ull;
    typedef long double ld;
    
    const int N = 1e5 + 10, M = 1e5 + 10;
    const ll inf = 1e17 + 10;
    
    int n, K, SS, EE;
    int s[M], e[M];
    
    int S, T, id[N];
    int head[M], nxt[M], to[M], w[M], flow[M], tot = 1;
    inline void add(int u, int v, int fl, int _w) {
        ++tot; nxt[tot] = head[u]; head[u] = tot; to[tot] = v;
        flow[tot] = fl, w[tot] = _w;
    }
    inline void adde(int u, int v, int fl, int _w) {
        add(u, v, fl, _w);
        add(v, u, 0, -_w);
    }
    
    namespace MCF {
        queue<int> q;
        int pre[M];
        ll d[M];  bool vis[M];
        inline bool spfa() {
            while(!q.empty()) q.pop();
            for (int i=1; i<=T; ++i) vis[i] = 0, d[i] = inf;
            vis[S] = 1; d[S] = 0; q.push(S);
            while(!q.empty()) {
                int top = q.front(); q.pop(); vis[top] = 0;
                for (int i=head[top]; i; i=nxt[i]) {
                    if(d[to[i]] > d[top] + w[i] && flow[i]) {
                        d[to[i]] = d[top] + w[i];
                        pre[to[i]] = i;
                        if(!vis[to[i]]) {
                            vis[to[i]] = 1;
                            q.push(to[i]);
                        }
                    }
                }
            }
            return d[T] < inf;
        }
        inline ll mcf() {
            int fl = 1e9; ll ret = 0;
            for (int i=pre[T]; i; i=pre[to[i^1]]) fl = min(fl, flow[i]);
            for (int i=pre[T]; i; i=pre[to[i^1]]) {
                flow[i] -= fl; flow[i^1] += fl;
                ret += 1ll * fl * w[i];
            }
            return ret;
        }
        inline ll main() {
            ll ans = 0;
            while(spfa()) ans += mcf();
            return ans;
        }
    }
    
    int main() {
        cin >> n >> K >> SS >> EE;
        ll sum = 0;
        for (int i=1; i<=n; ++i) {
            scanf("%d", &s[i]);
            sum += s[i];
        }
        for (int i=1; i<=n; ++i) {
            scanf("%d", &e[i]);
            e[i] -= s[i];
        }
        int mi = EE, mx = K - SS;
        int S0 = n+1; S = n+2; T = n+3;
        //  [mi, mx] 
        adde(S, S0, mx, 0);
        for (int i=1; i<=n; ++i) {
            if(i <= K) adde(S0, i, 1e9, 0);
            if(i+1 <= n) adde(i, i+1, mx-mi, 0);
            else adde(i, T, mx-mi, 0);
            if(i+K <= n) adde(i, i+K, 1, -e[i]);
            else adde(i, T, 1, -e[i]);
            id[i] = tot;
        }
        cout << sum - MCF::main() << endl;
        for (int i=1; i<=n; ++i) {
            if(flow[id[i]^1]) putchar('S');
            else putchar('E');
        }
        return 0;
    }
    View Code
  • 相关阅读:
    泛型接口协变和抗变
    泛型类功能
    泛型结构
    using 关键字给类和名称空间指定别名
    sqlite创建数据库问题
    sqlite命令
    必须输入大于0的整数
    最近在看c#本质论和B站上对应这本书的视频
    Linux系统管理笔记
    创建圆形类,其中包括set,get方法
  • 原文地址:https://www.cnblogs.com/galaxies/p/bzoj4842.html
Copyright © 2011-2022 走看看