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  • 【LeetCode】237. Delete Node in a Linked List

    Delete Node in a Linked List

    Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.

    Supposed the linked list is 1 -> 2 -> 3 -> 4 and you are given the third node with value 3, the linked list should become 1 -> 2 -> 4 after calling your function.

    后一个赋值给前一个,注意结尾的置空与删除。

    /**
     * Definition for singly-linked list.
     * struct ListNode {
     *     int val;
     *     ListNode *next;
     *     ListNode(int x) : val(x), next(NULL) {}
     * };
     */
    class Solution {
    public:
        void deleteNode(ListNode* node) {
            ListNode* cur = node;
            ListNode* post = cur->next; // except the tail, thus has access to the next
            while(true)
            {
                cur->val = post->val;
                if(post->next == NULL)
                {
                    cur->next = NULL;
                    return;
                }
                else
                {
                    cur = post;
                    post = post->next;
                }
            }
        }
    };

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  • 原文地址:https://www.cnblogs.com/ganganloveu/p/4648589.html
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