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  • leetcode刷题笔记一百八十四题 && 一百八十五题

    leetcode刷题笔记一百八十四题 && 一百八十五题

    源地址:

    184. 部门工资最高的员工

    185. 部门工资前三高的所有员工

    184问题描述:

    Employee 表包含所有员工信息,每个员工有其对应的 Id, salary 和 department Id。

    +----+-------+--------+--------------+
    | Id | Name | Salary | DepartmentId |
    +----+-------+--------+--------------+
    | 1 | Joe | 70000 | 1 |
    | 2 | Jim | 90000 | 1 |
    | 3 | Henry | 80000 | 2 |
    | 4 | Sam | 60000 | 2 |
    | 5 | Max | 90000 | 1 |
    +----+-------+--------+--------------+
    Department 表包含公司所有部门的信息。

    +----+----------+
    | Id | Name |
    +----+----------+
    | 1 | IT |
    | 2 | Sales |
    +----+----------+
    编写一个 SQL 查询,找出每个部门工资最高的员工。对于上述表,您的 SQL 查询应返回以下行(行的顺序无关紧要)。

    +------------+----------+--------+
    | Department | Employee | Salary |
    +------------+----------+--------+
    | IT | Max | 90000 |
    | IT | Jim | 90000 |
    | Sales | Henry | 80000 |
    +------------+----------+--------+
    解释:

    Max 和 Jim 在 IT 部门的工资都是最高的,Henry 在销售部的工资最高。

    # Write your MySQL query statement below
    SELECT B.name AS 'Department',
        A.name AS 'Employee',
        Salary FROM Employee AS A JOIN Department B ON A.DepartmentId = B.Id 
    WHERE  (A.DepartmentId , A.Salary) IN (
        SELECT DepartmentId, MAX(Salary) FROM Employee GROUP BY DepartmentId
    );
    

    185问题描述:

    SQL架构

    Employee 表包含所有员工信息,每个员工有其对应的工号 Id,姓名 Name,工资 Salary 和部门编号 DepartmentId

    +----+-------+--------+--------------+
    | Id | Name  | Salary | DepartmentId |
    +----+-------+--------+--------------+
    | 1  | Joe   | 85000  | 1            |
    | 2  | Henry | 80000  | 2            |
    | 3  | Sam   | 60000  | 2            |
    | 4  | Max   | 90000  | 1            |
    | 5  | Janet | 69000  | 1            |
    | 6  | Randy | 85000  | 1            |
    | 7  | Will  | 70000  | 1            |
    +----+-------+--------+--------------+
    

    Department 表包含公司所有部门的信息。

    +----+----------+
    | Id | Name     |
    +----+----------+
    | 1  | IT       |
    | 2  | Sales    |
    +----+----------+
    

    编写一个 SQL 查询,找出每个部门获得前三高工资的所有员工。例如,根据上述给定的表,查询结果应返回:

    +------------+----------+--------+
    | Department | Employee | Salary |
    +------------+----------+--------+
    | IT         | Max      | 90000  |
    | IT         | Randy    | 85000  |
    | IT         | Joe      | 85000  |
    | IT         | Will     | 70000  |
    | Sales      | Henry    | 80000  |
    | Sales      | Sam      | 60000  |
    +------------+----------+--------+
    

    解释:

    IT 部门中,Max 获得了最高的工资,Randy 和 Joe 都拿到了第二高的工资,Will 的工资排第三。销售部门(Sales)只有两名员工,Henry 的工资最高,Sam 的工资排第二。

    # Write your MySQL query statement below
    SELECT B.Name AS Department, A.Name AS Employee,A.Salary FROM 
    (SELECT dense_rank() OVER(PARTITION BY DepartmentId ORDER BY Salary DESC) AS RANKId, Name, Salary, DepartmentId FROM Employee) AS A JOIN Department AS B 
    ON A.DepartmentId = B.Id WHERE A.RANKId <= 3;
    
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  • 原文地址:https://www.cnblogs.com/ganshuoos/p/13669535.html
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