zoukankan      html  css  js  c++  java
  • java线程几个重要概念(死锁)

    思路是创建两个字符串a和b,再创建两个线程A和B,让每个线程都用synchronized锁住字符串(A先锁a,再去锁b;B先锁b,再锁a),如果A锁住a,B锁住b,A就没办法锁住b,B也没办法锁住a,这时就陷入了死锁。

    public class DeadLock {
        public static String obj1 = "obj1";
        public static String obj2 = "obj2";
        public static void main(String[] args){
            Thread a = new Thread(new Lock1());
            Thread b = new Thread(new Lock2());
            a.start();
            b.start();
        }    
    }
    class Lock1 implements Runnable{
        @Override
        public void run(){
            try{
                System.out.println("Lock1 running");
                while(true){
                    synchronized(DeadLock.obj1){
                        System.out.println("Lock1 lock obj1");
                        Thread.sleep(3000);//获取obj1后先等一会儿,让Lock2有足够的时间锁住obj2
                        synchronized(DeadLock.obj2){
                            System.out.println("Lock1 lock obj2");
                        }
                    }
                }
            }catch(Exception e){
                e.printStackTrace();
            }
        }
    }
    class Lock2 implements Runnable{
        @Override
        public void run(){
            try{
                System.out.println("Lock2 running");
                while(true){
                    synchronized(DeadLock.obj2){
                        System.out.println("Lock2 lock obj2");
                        Thread.sleep(3000);
                        synchronized(DeadLock.obj1){
                            System.out.println("Lock2 lock obj1");
                        }
                    }
                }
            }catch(Exception e){
                e.printStackTrace();
            }
        }
    }
    坚持
  • 相关阅读:
    对拍程序的写法
    单调队列模板
    [bzoj1455]罗马游戏
    KMP模板
    [bzoj3071]N皇后
    [bzoj1854][SCOI2010]游戏
    Manacher算法详解
    [bzoj2084][POI2010]Antisymmetry
    Python_sklearn机器学习库学习笔记(一)_一元回归
    C++STL学习笔记_(1)string知识
  • 原文地址:https://www.cnblogs.com/gaoSJ/p/12837013.html
Copyright © 2011-2022 走看看