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  • 排序总结归纳

    对于一个int数组,请编写一个归并排序算法,对数组元素排序。

    给定一个int数组A及数组的大小n,请返回排序后的数组。

    测试样例:
    [1,2,3,5,2,3],6
    [1,2,2,3,3,5]

    1、冒泡排序 O(n^2)

     1 class BubbleSort {
     2 public:
     3     int* bubbleSort(int* A, int n) {
     4         for(int i=0;i<n;i++){
     5             for(int j=i;j<n;j++){
     6                 int tmp;
     7                 if(A[i]>A[j]){
     8                     tmp = A[i];
     9                     A[i]= A[j];
    10                     A[j]= tmp;
    11                 }
    12             }
    13         }
    14         return A; 
    15     }
    16 };

    2、归并排序 O(nlogn)

     1 class MergeSort {
     2 public:
     3     
     4     int* mergeSort(int* A, int n) {
     5         int* tmp = new int[n];
     6         mergeSort1(A,0,n-1,tmp);
     7         delete []tmp;
     8         return A;
     9     }
    10     void mergeSort1(int* A,const int first,const int last,int* tmp){
    11         if(first < last){
    12             int mid = (first + last) / 2;
    13             mergeSort1(A,first,mid,tmp);
    14             mergeSort1(A,mid+1,last,tmp);
    15             merge(A,first,mid,last,tmp);
    16         }
    17     }
    18     
    19     void merge(int* A,const int first,const int mid,const int last,int* tmp){
    20         int i=0,j=0,k=0;
    21         for(i=first,j=mid+1;i<=mid && j<= last;){
    22             if(A[i]<A[j]) 
    23                 tmp[k++] = A[i++];
    24             else
    25                 tmp[k++] = A[j++];
    26         }
    27         while(i<=mid) tmp[k++] = A[i++];
    28         while(j<=last) tmp[k++] = A[j++];
    29         for(i=0;i<k;i++){
    30             A[first+i] = tmp[i];
    31         }
    32         
    33     }
    34 };

    3、快速排序 O(nlogn)

     1 class QuickSort {
     2 public:
     3     int* quickSort(int* A, int n) {
     4         quickSort1(A,0,n-1);
     5         return A;
     6     }
     7     void quickSort1(int* A,const int first,const int last){
     8         if(first<last){
     9             int mid = Sort(A,first,last);
    10             quickSort1(A,first,mid);
    11             quickSort1(A,mid+1,last);
    12         }
    13     }
    14     int Sort(int* A,const int first,const int last){
    15         int i=first;
    16         int j=last;
    17         int key = A[first];
    18         if(first < last){
    19             while(i<j){
    20                 while(i<j && key<=A[j])
    21                     j--;
    22                 if(i<j)
    23                     A[i++] = A[j];
    24                 while(i<j && key>=A[i])
    25                     i++;
    26                 if(i<j)
    27                     A[j--] = A[i];
    28             }
    29             A[i] = key;
    30         }
    31         return i;
    32     }
    33 };

     4、堆排序 O(nlogn)

     1 class HeapSort {
     2 public:
     3     int* heapSort(int* A, int n) {
     4         int len = n;
     5         for(int i=len/2-1;i>=0;i--)//bulid the heap
     6             heapAdjust(A,i,len);
     7         for(int i=len-1;i>=1;i--){// swap and adjust
     8             swap(A,0,i);
     9             heapAdjust(A,0,i);
    10         }
    11         return A;
    12     }
    13     void heapAdjust(int* A,int idx,int len){
    14         int left = 2*idx+1;
    15         int right = left+1;
    16         int largest = idx;
    17         
    18         if(left<len && A[left] > A[idx]) largest = left;
    19         if(right<len && A[right] > A[largest]) largest = right;
    20         if(largest != idx){
    21             swap(A,idx,largest);
    22             heapAdjust(A,largest,len);
    23         }
    24     }
    25     void swap(int* A,int a,int b){
    26         int tmp;
    27         tmp = A[a];
    28         A[a]= A[b];
    29         A[b]= tmp;
    30     }
    31 };

     5、希尔排序

     1 class ShellSort {
     2 public:
     3     int* shellSort(int* A, int n) {
     4         for(int step=n/2;step>=1;step /= 2){
     5             for(int i=0;i<n;i+=step){
     6                 int tmp = A[i];
     7                 int j = i-step;
     8                 for(;j>=0;j-=step){
     9                     if(A[j]>tmp)
    10                         A[j+step] = A[j];
    11                     else
    12                         break;
    13                 }
    14                 A[j+step] = tmp;
    15             }
    16         }
    17         return A;
    18     }
    19 };
    转载请注明出处: C++博客园:godfrey_88 http://www.cnblogs.com/gaobaoru-articles/
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  • 原文地址:https://www.cnblogs.com/gaobaoru-articles/p/5247781.html
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