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  • MySQL查询


    -- 查询练习
    -- 查询所有字段
    -- select * from 表名;
    select * from students;

    -- 查询指定字段
    -- select 列1,列2,... from 表名;
    select name,gender from students;

    -- 使用 as 给字段起别名
    -- select 字段 as 名字.... from 表名;
    select name as "姓名",gender as "性别" from students;

    -- select 表名.字段 .... from 表名;
    select name as "姓名",gender as "性别" from students as s;


    -- 可以通过 as 给表起别名
    -- select 别名.字段 .... from 表名 as 别名;
    select s.name as "姓名",s.gender as "性别" from students as s;

    失败的select students.name, students.age from students as s;

    -- 消除重复行(查性别)

    -- distinct 字段
    select gender from students;
    select distinct gender from students;

    -- 条件查询
    -- 比较运算符
    -- select .... from 表名 where .....
    -- >
    -- 查询大于18岁的信息
    select * from students where age > 18;

    -- <
    -- 查询小于18岁的信息
    select * from students where age < 18;

    -- >=
    -- <=
    -- 查询小于或者等于18岁的信息
    select * from students where age <= 18;
    -- =
    -- 查询年龄为18岁的所有学生的名字
    (区别)select * from students where age = 18;


    -- != 或者 <>
    select * from students where age != 18;

    -- 逻辑运算符
    -- and
    -- 18和28之间的所以学生信息
    select * from students where age >=18 and age <=28;

    失败 select * from students where age>18 and <28;

    -- 18岁以上的女性
    select * from students where age > 18 and gender = 2;

    -- or
    -- 18以上或者身高高过180(包含)以上
    select * from students where age > 18 or height >= 180;


    -- not
    -- 不在 18岁以上的女性 这个范围内的信息
    -- select * from students where not age>18 and gender=2;
    select * from students where not (age > 18 and gender = 2);


    -- 模糊查询(where name like 要查询的数据)
    -- like
    -- % 替换任意个
    -- _ 替换1个
    -- 查询姓名中 以 "小" 开始的名字
    select * from students where name like "小%";

    -- 查询姓名中 有 "小" 所有的名字
    select * from students where name like "%小%";

    -- 查询有2个字的名字
    select * from students where name like "__";

    -- 查询有3个字的名字
    select * from students where name like "___";

    -- 查询至少有2个字的名字
    select * from students where name like "__%";

    -- 范围查询
    -- in (1, 3, 8)表示在一个非连续的范围内
    -- 查询 年龄为18、34的姓名
    select * from students where age =18 or age = 34;
    select * from students where age in (18,34);

    -- not in 不非连续的范围之内
    -- 年龄不是 18、34岁之间的信息
    select * from students where age not in (18,34);

    (注意)select name from students where not age in (18,34);


    -- between ... and ...表示在一个连续的范围内
    -- 查询 年龄在18到34之间的的信息
    select * from students where age between 18 and 34;

    -- not between ... and ...表示不在一个连续的范围内
    -- 查询 年龄不在在18到34之间的的信息
    select * from students where age not between 18 and 34;

    失败的select * from students where age not (between 18 and 34);

    -- 空判断
    -- 判空is null
    -- 查询身高为空的信息
    select * from students where height is null;

    -- 判非空is not null
    select * from students where height is not null;

    失败select * from students where height not is null;

    -- 排序
    -- order by 字段
    -- asc从小到大排列,即升序
    -- desc从大到小排序,即降序

    -- 查询年龄在18到34岁之间的男性,按照年龄从小到大到排序
    select * from students where (age between 18 and 34) and gender = 1 order by age asc;
    -- 查询年龄在18到34岁之间的女性,身高从高到矮排序
    select * from students where (age between 18 and 34) and gender = 2 order by height desc;

    -- order by 多个字段
    -- 查询年龄在18到34岁之间的女性,身高从高到矮排序, 如果身高相同的情况下按照年龄从小到大排序
    select * from students where (age between 18 and 34) and gender = 2 order by height desc,age asc;

    -- 查询年龄在18到34岁之间的女性,身高从高到矮排序, 如果身高相同的情况下按照年龄从小到大排序,
    -- 如果年龄也相同那么按照id从大到小排序
    select * from students where (age between 18 and 34) and gender = 2 order by height desc,age asc,id desc;


    -- 聚合函数
    -- 总数
    -- count
    -- 查询男性有多少人,女性有多少人
    select count(*) from students where gender = 1;
    select count(*) from students where gender = 2;

    -- 最大值
    -- max
    -- 查询最大的年龄
    select max(age) from students;

    -- 查询女性的最高 身高
    select max(height) from students where gender = 2;

    -- 最小值
    -- min
    select min(height) from students where gender = 2;

    -- 求和
    -- sum
    -- 计算所有人的年龄总和
    select sum(age) from students;


    -- 平均值
    -- avg
    -- 计算平均年龄
    select avg(age) from students;


    -- 计算平均年龄 sum(age)/count(*)


    -- 四舍五入 round(123.23 , 1) 保留1位小数
    -- 计算所有人的平均年龄,保留3位小数
    select round(avg(age),3) from students;

    -- 计算男性的平均身高 保留2位小数
    select round(avg(height),2) from students where gender = 1;

    -- 分组

    -- group by
    -- 按照性别分组,查询所有的性别
    select gender from students group by gender;
    -- select name,gender from students group by gender;
    -- 失败select * from students group by gender;
    select * from students group by gender;
    -- 计算每种性别中的人数
    select count(*),gender from students group by gender;

    -- group_concat(...)
    -- 查询同种性别中的姓名
    select group_concat(name),gender from students group by gender;

    -- 查询每组性别的平均年龄
    select avg(age),gender from students group by gender;

    -- having(注意having和group by)
    (!)-- 查询平均年龄超过30岁的性别,以及姓名 having avg(age) > 30
    select gender,group_concat(name) from students
    group by gender
    having avg(age) > 30;

    -- 查询每种性别中的人数多于2个的信息
    select gender,group_concat(name) from students group by gender having count(*) > 2;

    -- with rollup 汇总的作用(了解)
    select gender,count(*) from students group by gender with rollup;

    -- 分页
    -- limit start, count

    -- 限制查询出来的数据个数
    -- 查询前5个数据
    select * from students limit 5;

    -- 每页显示2个,第1个页面
    select * from students limit 0,2;

    -- 每页显示2个,第2个页面
    select * from students limit 2,2;

    -- 每页显示2个,第3个页面
    select * from students limit 4,2;

    -- 每页显示2个,第4个页面
    select * from students limit 6,2;

    -- 每页显示2个,显示第6页的信息, 按照年龄从小到大排序(limit 必须写到sql语句的最后)
    错误1 select * from students limit 10,2 order by age asc;

    -- 工作错误的写法
    错误2 select * from students limit 2*(6-1),2;

    -- limit 放在最后面(注意)


    -- 连接查询
    -- inner join ... on
    -- select ... from 表A inner join 表B;
    select * from students inner join classes;

    -- 查询 有能够对应班级的学生以及班级信息
    select * from students inner join classes on students.cls_id = classes.id;

    -- 按照要求显示姓名、班级
    select students.name,classes.name from students inner join classes on students.cls_id = classes.id;

    -- 给数据表起名字
    select s.name,c.name from students as s inner join classes as c on s.cls_id = c.id;

    -- 查询 有能够对应班级的学生以及班级信息,显示学生的所有信息 students.*,只显示班级名称 classes.name.
    select s.*,c.name from students as s inner join classes as c on s.cls_id = c.id;

    -- 在以上的查询中,将班级姓名显示在第1列
    select c.name,s.* from students as s inner join classes as c on s.cls_id = c.id;

    -- 查询 有能够对应班级的学生以及班级信息, 按照班级进行排序
    -- select c.xxx s.xxx from students as s inner join clssses as c on .... order by ....;
    select c.name,s.* from students as s inner join classes as c on s.cls_id = c.id order by c.name;

    -- 当时同一个班级的时候,按照学生的id进行从小到大排序
    select c.name,s.* from students as s inner join classes as c on s.cls_id = c.id order by c.name,id asc;

    -- left join
    -- 查询每位学生对应的班级信息
    select * from students left join classes on students.cls_id = classes.id;
    -- select * from students right join classes on students.cls_id = classes.id;

    -- 查询没有对应班级信息的学生
    -- select ... from xxx as s left join xxx as c on..... where .....
    -- select ... from xxx as s left join xxx as c on..... having .....
    select * from students left join classes on students.cls_id = classes.id where classes.name is null;

    (注意)不建议使用 select * from students left join classes on students.cls_id=classes.id having classes.id is null;

    -- right join on
    -- 将数据表名字互换位置,用left join完成


    -- 子查询
    -- 标量子查询: 子查询返回的结果是一个数据(一行一列)
    -- 列子查询: 返回的结果是一列(一列多行)

    -- 行子查询: 返回的结果是一行(一行多列)

    -- 查询出高于平均身高的信息(height)
    -- 1 查出平均身高
    select avg(height) from students ; -- 172
    -- 2 查出高于平均身高的信息
    select * from students where height >(select avg(height) from students) ;

    -- 查询学生的班级号能够对应的 学生名字
    -- select name from students where cls_id in (select id from classes);
    -- 1 查出所有的班级id
    select id from classes; -- 1,2
    -- 2 查出能够对应上班级号的学生信息
    select * from students where cls_id in (select id from classes);


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  • 原文地址:https://www.cnblogs.com/gaodenghan/p/13780202.html
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