算法——二分查找变形题

给一个已经排好序的数组，在任意位置打断点后交换前后两个子数组，以此作为输入，输出n在该数组中的位置

eg：

输入 arr=[7,8,9,10,1000,10003,40000,1,2,3,4,5,6] n=9

输出 2

public class test {
    public static int findnumber(int[] num,int n){
        int half=num.length/2;
        int low=0;
        int high=num.length-1;

　　　　　while(low<=high){
            if(n==num[half]){
                return half;
            }
            //5,10,4
            if(num[low]<num[half]){
                if(n>num[low]&&n<num[half]){
                    high=half;
                    half=(low+half)/2;
                }else{
                    low=half;
                    half=(half+high)/2;
                }
            }
            else if(num[half]<num[high]){
                if(n>num[half]&&n<num[high]){
                    low=half;
                    half=(half+high)/2;
                }else{
                    high=half;
                    half=(half+low)/2;
                }
            }
        }
        return -1;
    }
    public static void main(String[] args) {
        int[] arr={7,8,9,10,1000,10003,40000,1,2,3,4,5,6};
        int n=9;
        int index = findnumber(arr, n);
        System.out.println(index);
    }
}