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  • P1074 靶形数独

    #include <bits/stdc++.h>
    #define searchnext(x, y) y == 9 ? search(x + 1, 1) : search(x, y + 1)
    using namespace std;
    long long ans = 0;
    int a[10][10];
    void search(int, int);
    void calc() {
      long long tmp = 0;
      for (int i = 1; i <= 9; i++) {
        for (int j = 1; j <= 9; j++) {
          if (i == 1 || i == 9 || j == 1 || j == 9) {
            tmp += 6 * a[i][j];
          } else if (abs(i - 9) == 1 || abs(i - 9) == 7 || abs(j - 9) == 1 ||
                     abs(j - 9) == 7) {
            tmp += 7 * a[i][j];
          } else if (abs(i - 9) == 2 || abs(i - 9) == 6 || abs(j - 9) == 2 ||
                     abs(j - 9) == 6) {
            tmp += 8 * a[i][j];
          } else if (abs(i - 9) == 5 || abs(i - 9) == 3 || abs(j - 9) == 5 ||
                     abs(j - 9) == 3) {
            tmp += 9 * a[i][j];
          } else
            tmp += 10 * a[i][j];
        }
      }
      ans = max(ans, tmp);
    }
    bool pd(int x, int y, int k) {
      for (int i = 1; i <= 9; i++)
        if (a[x][i] == k || a[i][y] == k)
          return 0;
      for (int i = (x - 1) / 3 * 3 + 1; i <= (x - 1) / 3 * 3 + 3; i++)
        for (int j = (y - 1) / 3 * 3 + 1; j <= (y - 1) / 3 * 3 + 3; j++)
          if (a[i][j] == k)
            return 0;
      return 1;
    }
    void search(int x, int y) {
      if (x == 10 && y == 1)
        calc();
      if (a[x][y] != 0) {
        searchnext(x, y);
      } else {
        for (int i = 9; i >= 1; i--)
          if (pd(x, y, i)) {
            a[x][y] = i;
            searchnext(x, y);
            a[x][y] = 0;
          }
      }
    }
    int main() {
      freopen("input.in", "r", stdin);
      for (int i = 1; i <= 9; i++)
        for (int j = 1; j <= 9; j++)
          scanf("%d", &a[i][j]);
      search(1, 1);
      if (ans)
        cout << ans;
      else
        cout << -1;
      return 0;
    }
    
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  • 原文地址:https://www.cnblogs.com/gengchen/p/6071194.html
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