zoukankan      html  css  js  c++  java
  • HDU 4968 Improving the GPA

    枚举。

      枚举每个分段有多少个科目,对每个枚举的状态判断是否满足条件,对满足条件的取其中最大和最小值。

     1 #include <iostream>
     2 #include <cstring>
     3 #include <cstdio>
     4 #include <cmath>
     5 using namespace std;
     6 
     7 const double eps=1e-8;
     8 
     9 int main (){
    10     int t;
    11     int a,n;
    12     //cin>>t;
    13     scanf ("%d",&t);
    14     while (t--){
    15         //cin>>a>>n;
    16         scanf ("%d%d",&a,&n);
    17         int sum=a*n;
    18         double maxn,minn;
    19         int mas=n*4,mis=n*8;
    20         for (int i=0;i<=n;i++){
    21             for (int j=0;j<=n;j++){
    22                 for (int k=0;k<=n;k++){
    23                     for (int o=0;o<=n;o++){
    24                         if (n>=i+j+k+o&&i*100+j*84+k*79+o*74+(n-i-j-k-o)*69>=sum&&i*85+j*80+k*75+o*70+(n-i-j-k-o)*60<=sum){
    25                             int temp=i*8+j*7+k*6+o*5+(n-i-j-k-o)*4;
    26                             mas=temp>mas?temp:mas;
    27                             mis=temp<mis?temp:mis;//cout<<i<<" "<<j<<" "<<k<<" "<<o<<" "<<n-i-j-k-o<<":"<<temp*1.0/n/2<<endl;
    28                         }
    29                     }
    30                 }
    31             }
    32         }
    33         minn=1.0*mis/n/2+eps;
    34         maxn=1.0*mas/n/2+eps;
    35         printf ("%.4f %.4f
    ",minn,maxn);
    36     }
    37     return 0;
    38 }
  • 相关阅读:
    BEC listen and translation exercise 44
    中译英12
    BEC listen and translation exercise 43
    中译英11
    BEC listen and translation exercise 42
    中译英10
    BEC listen and translation exercise 41
    中译英9
    BEC listen and translation exercise 40
    中译英8
  • 原文地址:https://www.cnblogs.com/gfc-g/p/3926474.html
Copyright © 2011-2022 走看看