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  • sql server 查询本周、本月所有天数的数据

    查询本月所有的天数:

    --本月所有的天数
    select convert(varchar(10),dateadd(DAY,t2.number,t1.day),120) day from 
    (select substring(convert(varchar,GETDATE(),120),1,7)+'-01' day) t1, 
    (select number from MASTER..spt_values WHERE TYPE='P' AND number>=0 and number<=31) t2 
    where convert(varchar(10),dateadd(DAY,t2.number,t1.day),120) like substring(convert(varchar,GETDATE(),120),1,7)+'%'

    查询本周所有的天数:

     select date=convert(varchar(10),dateadd(wk, datediff(wk,0,getdate()), 0),120)
    union all select date=convert(varchar(10),dateadd(wk, datediff(wk,0,getdate()), 1),120)
    union all select date=convert(varchar(10),dateadd(wk, datediff(wk,0,getdate()), 2),120)
    union all select date=convert(varchar(10),dateadd(wk, datediff(wk,0,getdate()), 3),120)
    union all select date=convert(varchar(10),dateadd(wk, datediff(wk,0,getdate()), 4),120)
    union all select date=convert(varchar(10),dateadd(wk, datediff(wk,0,getdate()), 5),120)
    union all select date=convert(varchar(10),dateadd(wk, datediff(wk,0,getdate()), 6),120)


    示例:

    如下图所示,有表MO_Orders,字段:BookTime,Number,Count,有如下数据。

    查询出本周的每天的数据总和,语句如下:

     with t as 
    ( 
        select date=convert(varchar(10),dateadd(wk, datediff(wk,0,getdate()), 0),120)
        union all select date=convert(varchar(10),dateadd(wk, datediff(wk,0,getdate()), 1),120)
        union all select date=convert(varchar(10),dateadd(wk, datediff(wk,0,getdate()), 2),120)
        union all select date=convert(varchar(10),dateadd(wk, datediff(wk,0,getdate()), 3),120)
        union all select date=convert(varchar(10),dateadd(wk, datediff(wk,0,getdate()), 4),120)
        union all select date=convert(varchar(10),dateadd(wk, datediff(wk,0,getdate()), 5),120)
        union all select date=convert(varchar(10),dateadd(wk, datediff(wk,0,getdate()), 6),120)
    )
    select id=ROW_NUMBER()OVER(ORDER BY t1.date),
            DATENAME(weekday,t1.date) as weekday,
            t1.date,
            Numbers=sum(isnull(t2.Number,0)),  
            Count=sum(isnull(t2.Count,0)) 
    from t t1 
    left join
    (  
        select substring(convert(varchar,BookTime,120),1,11) as BookTime,
                Number,Count 
        from  MO_Orders 
        where datediff(wk,BookTime-1,getdate()) = 0  
        )
        t2 
    on t1.date= substring(convert(varchar,t2.BookTime,120),1,11)
    group by t1.date 

    查询效果如下图,其中 weekday为星期,此图还需替换,稍后补上:

    示例:如下图所示,有表: MO_Orders,字段:BookTime,Cost,Count 。

    查询本月的所有数据总和(其中:total=Cost*Count)。

    查询出本月的每天的数据总和,显示每天的,查询语句如下:

     with t as 
    ( 
      select convert(varchar(10),dateadd(DAY,t2.number,t1.day),120) date from 
        (select substring(convert(varchar,GETDATE(),120),1,7)+'-01' day) t1, 
        (select number from MASTER..spt_values WHERE TYPE='P' AND number>=0 and number<=31) t2 
        where convert(varchar(10),dateadd(DAY,t2.number,t1.day),120) like substring(convert(varchar,GETDATE(),120),1,7)+'%'
    )
    select id=ROW_NUMBER()OVER(ORDER BY t1.date),
            t1.date,
            CostTotal=sum(isnull(t2.CostTotal,0))
    from t t1 
    left join 
    (    
        select BookTime,sum(CostTotal) as CostTotal from 
        (
            select substring(convert(varchar,BookTime,120),1,11) as BookTime,
                    Cost*Count as CostTotal 
            from  MO_Orders 
            where datediff(month,BookTime,getdate()) = 0 
        ) o group by BookTime
    ) t2
    on t1.date= t2.BookTime 
    group by t1.date

    查询结果如下图:

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  • 原文地址:https://www.cnblogs.com/ggll611928/p/6410188.html
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