1.设计思路
接着上次的程序写，这周出题可以加入括号，但是带括号以及分数答案的计算还没有完成，还在思考，另外这次加入了数据库，可以将题目及答案存入数据表中，没有答案的题存为null值，连上数据库，用SQL语句就能存入。
2.源代码
1 <%@ page language="java" contentType="text/html; charset=UTF-8" 2 pageEncoding="UTF-8" %> 3 <%@ page import="jisuan.*" import="java.sql.*" import="chuti.*" import="dbcoon.*" %> 4 <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> 5 <html> 6 <head> 7 <meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1"> 8 <title>自动出题</title> 9 </head> 10 11 <body> 12 <% 13 String type = request.getParameter("type"); 14 int cc=Integer.parseInt(request.getParameter("chengchu")); 15 int kuohao=Integer.parseInt(request.getParameter("kuohao")); 16 int fw=Integer.parseInt(request.getParameter("fanwei")); 17 int num=Integer.parseInt(request.getParameter("num")); 18 int chutishu=Integer.parseInt(request.getParameter("chutishu")); 19 int da=Integer.parseInt(request.getParameter("daan")); 20 int yushu=Integer.parseInt(request.getParameter("yushu")); 21 int fushu=Integer.parseInt(request.getParameter("fushu")); 22 23 JspWriter mout=pageContext.getOut(); 24 String []a=new String [chutishu]; 25 String []daan=new String[chutishu]; 26 27 //连数据库 28 String driverName="com.microsoft.sqlserver.jdbc.SQLServerDriver"; 29 String dbURL="jdbc:sqlserver://localhost:1433;DatabaseName=Web"; 30 String userName="sa"; 31 String userPwd="ghs123456"; 32 Class.forName(driverName); 33 Connection dbConn=DriverManager.getConnection(dbURL,userName,userPwd); 34 35 Statement st = dbConn.createStatement(); 36 37 //出题 38 for(int j=0;j<chutishu;j++){ 39 if(type.equals("zhengshu")) 40 a[j]=Chuti.putong(num,cc,fw); 41 else if(type.equals("zhenfenshu")) 42 a[j]=Chuti.zhenfenshu(num,cc); 43 else if(type.equals("douyou")){ 44 int m=(int)(Math.random()*2+1); 45 if(m==1) 46 a[j]=Chuti.putong(num,cc,fw); 47 else if(m==2) 48 a[j]=Chuti.zhenfenshu(num,cc); 49 } 50 //查重 51 for(int k=0;k<j;k++){ 52 if(a[k].equals(a[j])) 53 {j--;break;} 54 else 55 continue; 56 } 57 //加括号 58 if(kuohao==1) 59 a[j]=Chuti.kuohao(a[j],num); 60 //计算结果(不带括号) 61 if(kuohao==0) 62 daan[j]=String.valueOf(Zhengshujisuan.fun1(a[j])); 63 //多元运算结果无限循环处理 64 if(type.equals("zhengshu")&&num>2&&kuohao==0){ 65 if (daan[j].length()-daan[j].indexOf(".")>5) 66 j--; 67 else 68 continue; 69 } 70 //二元运算有无余数处理 71 if(type.equals("zhengshu")&&yushu==0&&num==2){ 72 if (daan[j].length()-daan[j].indexOf(".")>2) 73 j--; 74 else 75 continue; 76 } 77 //有无负数处理 78 if(type.equals("zhengshu")&&fushu==0&&kuohao==0){ 79 if (daan[j].charAt(0)=='-') 80 j--; 81 } 82 } 83 //输出题目并存入数据库 84 for(int i=0;i<chutishu;i++){ 85 mout.print((i+1)+". "+a[i]+"<br>"); 86 87 } 88 //如果是整数输出答案 89 mout.print("答案：<br>"); 90 //有余数输出带余数的答案 91 if(type.equals("zhengshu")&&yushu==1&&num==2){ 92 for(int i=0;i<chutishu;i++){ 93 if(daan[i].length()-daan[i].indexOf(".")>2){ 94 int first=Integer.parseInt(a[i].substring(0,a[i].indexOf("÷"))); 95 int second=Integer.parseInt(a[i].substring(a[i].indexOf("÷")+1,a[i].length())); 96 daan[i]=first/second+"········"+first%second; 97 } 98 } 99 } 100 if(type.equals("zhengshu")&&da==1){ 101 for(int i=0;i<chutishu;i++){ 102 mout.print(i+1+". "+daan[i]+"<br>"); 103 } 104 } 105 for(int i=0;i<chutishu;i++){ 106 String sqlStr="INSERT INTO 出题 (No,题目,答案)VALUES('"+(i+1)+"' , '" + a[i] + "' ,'" + daan[i] + "' )"; 107 st.executeUpdate(sqlStr); 108 } 109 st.close(); 110 dbConn.close(); 111 112 %> 113 </body> 114 </html>
3.截图
