zoukankan      html  css  js  c++  java
  • SQL的经典算法

    1 SQL分页查询,每页10个数据,取第三页

    A) 如果有id列

    select top(10)  * from Spider_Hotel

    where Spider_Hotel.HotelId not in

    ( select top (10*2) Spider_Hotel.HotelId from Spider_Hotel)

    B) 如果没有id列

    select top (10) * from

    (select ROW_NUMBER() over (order by Name) as Row,* from Spider_Hotel)

     a

    where Row>10*2

    C) 如果有id列

    select top (10) * from Spider_Hotel

    where HotelId >(select max(HotelId)

    from (select top (10*2) HotelId from Spider_Hotel order by HotelId) as a

    )

    2,数据库删除重复记录。

    a, 如果有id列 a,b,c 重复

    Delete  from table  where id not in (select max (id) from table group a,b,c)

    b,  如果没有id列a,b,c 重复 .用row_number() over 函数,制造个Id列

       With Tab as

         Select  row_number() over (order by a) as Row,a,b,c from table

    Delete from Tab

    Where  Row not in (selete max(Row) from Tab group a,b,c)

    3,Count函数。

      SELECT COUNT(*),COUNT(FNumber),COUNT(FName) FROM T_Employee

    COUNT(*)统计的是结果集的总条数,而

    COUNT(FName)统计的则是除了结果集中FName 不为空值(也就是不等于NULL)的记录的总

    条数,如果Fname有为空COUNT(*) 不等于COUNT(FNumber)

    4,求一公司年龄在20-30,40-60岁这两个年龄段的人数,行列转换

    select SUM(Young) as Young ,SUM(Old) as Old from (

      select

      Users_age,

      sum(case when Users_age between 1 and 3 then 1 else 0 end) as Young,

      sum(case when Users_age between 4 and 6then 1 else 0 end) as Old

    from Users

    group by Users_age) as s

    //  显示名字,不显示人数,我感觉数据库语句是一个一个判断下去的

    select

      years,

      case when age between 20 and 30 then name else '---' end as [20-30],

      case when age between 30 and 40 then name else '---' end as [30-40],

      case when age between 40 and 50 then name else '---' end as [40-50]

    from info

    group by years,name,age

    5,连续三天的记录   (查询连续三天抽取同一家酒店同一入住时间的免费房的人员记录)

    select Member_Code from

    dbo.Member a where

    exists

    (

       select * from Member b

       where b.Register_Date = DATEADD(D,1,a.Register_Date) and a.Member_Code=b.Member_Code

    )

    and

    exists

    (

       select * from Member b

       where b.Register_Date = DATEADD(D,2,a.Register_Date) and a.Member_Code=b.Member_Code

    )

    group by Member_Code

    6,查询表结构   (查询一个数据库所有的数据库表 字段类型 字段大小)

    --查询表结构

    select Dense_Rank() over (order by o.name) as table_order, ROW_NUMBER() over (partition by o.id order by o.name) as column_order,

    o.name as table_name, c.name as column_name, t.name+'['+ convert(varchar, c.[length])+']' as column_type

    from sysobjects o inner join syscolumns c

    inner join systypes t on c.xusertype=t.xusertype

    on o.id=c.id

    where o.xtype='U'

    order by o.name

    --查询数据库表

    select * from dbo.sysobjects

    where sysobjects.xtype ='U'

    --查询数据库列

    select * from syscolumns

    where id=21575115

    7,截止今天的销售额  (一个超市每天都有营业额。列出每天的营业额和截止到每天的总营业额。)

    (比如,第一天 营业额 10 总营业额 10,第二天 营业额20 总营业额 30;第二天 营业额 10 总营业额 40)

    select dates,(select SUM(moneys) from Table as TT

    where TT.dates <= T.dates)  from Table as T

    8,全局临时表,防止用户两地登录。

    --全局临时表防止用户地登录,但是如果用户量大,这很可能消耗大量资源。

    --用户登录,就根据用户Id创建个临时表,如果用户账户异地登录,就会发现

    --这张临时表已经存在,返回,提示登录不成功。用户退出系统后,临时表自动消失。

    alter proc gp_findtemptable

    @v_userid varchar(6),@i_out int output

    as

    declare @v_sql varchar(100)

    if object_id('tempdb.dbo.##'+@v_userid) is null

    begin

    set @v_sql = 'create table ##'+@v_userid+'(userid varchar(6))'

    exec (@v_sql)

    set @i_out = 0

    end

    else

    set @i_out = 1

    declare @I int

    exec gp_findtemptable 'T00001',@I output

    select @I

    9,查找指定节点的所有子节点的子节点。

    create table os(id int,parentid int,desn varchar(10))

    --自己不能是自己的节点,否则进入死循环。

    alter function f_cid(@id int)

    returns varchar(500)

    as

    begin

      declare @t table(id int,desn varchar(10),parentid int,lev int)

      declare @lev int

      set @lev=1

      insert into @t select *,@lev from os where id=@id

      while(@@rowcount>0)

      begin

      set @lev=@lev+1

      insert into @t select a.*,@lev from os a,@t b

      where a.parentid=b.id and b.lev=@lev-1

      end

      declare @cids varchar(500)

      select @cids=isnull(@cids+',','')+ltrim(id) from @t order by lev

      return @cids

    end

    go

    执行查询

    select *,ids=dbo.f_cid(id) from os

    转载:https://blog.csdn.net/slowlifes/article/details/7973904

  • 相关阅读:
    node03
    node02
    node01
    Vue-router重修02
    Vue-router重修01
    Vue重修02
    VUE重修01
    利用表达式目录树进行实体映射
    C#托管堆和垃圾回收
    C# 异步锁
  • 原文地址:https://www.cnblogs.com/gilgamos/p/10123197.html
Copyright © 2011-2022 走看看