1、a表
2、b表
3、连接(a_u_id 对应b表的b_id)
select a.a_id,a.a_u_id,group_concat(b.b_name) from a_tb a left join b_tb b on find_in_set(b.b_id,a.a_u_id) group by a.a_id
4、效果