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  • Delete Node in a Linked List

    Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.

    Supposed the linked list is 1 -> 2 -> 3 -> 4 and you are given the third node with value 3, the linked list should become 1 -> 2 -> 4 after calling your function.

    /**
     * Definition for singly-linked list.
     * struct ListNode {
     *     int val;
     *     ListNode *next;
     *     ListNode(int x) : val(x), next(NULL) {}
     * };
     */
    class Solution {
    public:
        void deleteNode(ListNode* node) {
            //实际上只要将下一个节点的值覆盖当前节点,然后删除下一个节点就好了。注意这样不适用于尾节点
            node->val = node->next->val;
            node->next = node->next->next;
           
        }
    };

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  • 原文地址:https://www.cnblogs.com/gofighting/p/5033176.html
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