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  • 网络流

    1.最大流

    ps:直接以题目来看模板的使用

    POJ - 1459 Power Network(最大流)(模板)

    d.看了好久,囧。

    n个节点,np个源点,nc个汇点,m条边(对应代码中即节点u 到节点v 的最大流量为z)

    求所有汇点的最大流。

    s.多个源点,多个汇点的最大流。

    建立一个超级源点、一个超级汇点,然后求超级源点到超级汇点的最大流即可。

    c.SAP邻接矩阵形式:

    /*
    SAP算法(矩阵形式)
    结点编号从0开始
    */
    #include<iostream>
    #include<stdio.h>
    #include<string.h>
    using namespace std;
    
    const int MAXN=128;
    int maze[MAXN][MAXN];
    int gap[MAXN],dis[MAXN],pre[MAXN],cur[MAXN];
    int sap(int start,int end,int nodenum){
        memset(cur,0,sizeof(cur));
        memset(dis,0,sizeof(dis));
        memset(gap,0,sizeof(gap));
        int u=pre[start]=start,maxflow=0,aug=-1;
        gap[0]=nodenum;
        while(dis[start]<nodenum){
            loop:
                for(int v=cur[u];v<nodenum;v++)
                    if(maze[u][v]&&dis[u]==dis[v]+1){
                        if(aug==-1||aug>maze[u][v])aug=maze[u][v];
                        pre[v]=u;
                        u=cur[u]=v;
                        if(v==end){
                            maxflow+=aug;
                            for(u=pre[u];v!=start;v=u,u=pre[u]){
                                maze[u][v]-=aug;
                                maze[v][u]+=aug;
                            }
                            aug=-1;
                        }
                        goto loop;
                    }
                int mindis=nodenum-1;
                for(int v=0;v<nodenum;v++)
                    if(maze[u][v]&&mindis>dis[v]){
                        cur[u]=v;
                        mindis=dis[v];
                    }
                if((--gap[dis[u]])==0)break;
                gap[dis[u]=mindis+1]++;
                u=pre[u];
        }
        return maxflow;
    }
    
    int main(){
        int n,np,nc,m;//节点总数,源点,汇点,边数
        int u,v,z;//节点u,节点v,最大流量z
        char str[5];//处理空格
        int sp,sc;//超级源点,超级汇点
    
        while(~scanf("%d%d%d%d",&n,&np,&nc,&m)){
            memset(maze,0,sizeof(maze));
            for(int i=0;i<m;++i){
                scanf("%1s%d%1s%d%1s%d",str,&u,str,&v,str,&z);
                maze[u][v]=z;
            }
    
            //建立超级源点
            sp=n++;
            for(int i=0;i<np;++i){
                scanf("%1s%d%1s%d",str,&u,str,&z);
                maze[sp][u]=z;
            }
            //建立超级汇点
            sc=n++;
            for(int i=0;i<nc;++i){
                scanf("%1s%d%1s%d",str,&u,str,&z);
                maze[u][sc]=z;
            }
            printf("%d
    ",sap(sp,sc,n));
        }
        return 0;
    }
    View Code

    c2.SAP邻接矩阵形式2:

    /*
    保留原矩阵,可用于多次使用最大流
    SAP邻接矩阵形式
    点的编号从0开始
    增加个flow数组,保留原矩阵maze,可用于多次使用最大流
    */
    #include<iostream>
    #include<stdio.h>
    #include<string.h>
    using namespace std;
    
    const int MAXN=128;
    int maze[MAXN][MAXN];
    int gap[MAXN],dis[MAXN],pre[MAXN],cur[MAXN];
    int flow[MAXN][MAXN];//存最大流的容量
    int sap(int start,int end,int nodenum){
        memset(cur,0,sizeof(cur));
        memset(dis,0,sizeof(dis));
        memset(gap,0,sizeof(gap));
        memset(flow,0,sizeof(flow));
        int u=pre[start]=start,maxflow=0,aug=-1;
        gap[0]=nodenum;
        while(dis[start]<nodenum){
            loop:
                for(int v=cur[u];v<nodenum;v++)
                    if(maze[u][v]-flow[u][v]&&dis[u]==dis[v]+1){
                        if(aug==-1||aug>maze[u][v]-flow[u][v])aug=maze[u][v]-flow[u][v];
                        pre[v]=u;
                        u=cur[u]=v;
                        if(v==end){
                            maxflow+=aug;
                            for(u=pre[u];v!=start;v=u,u=pre[u]){
                                flow[u][v]+=aug;
                                flow[v][u]-=aug;
                            }
                            aug=-1;
                        }
                        goto loop;
                    }
                int mindis=nodenum-1;
                for(int v=0;v<nodenum;v++)
                if(maze[u][v]-flow[u][v]&&mindis>dis[v]){
                    cur[u]=v;
                    mindis=dis[v];
                }
                if((--gap[dis[u]])==0)break;
                gap[dis[u]=mindis+1]++;
                u=pre[u];
        }
        return maxflow;
    }
    
    int main(){
        int n,np,nc,m;//节点总数,源点,汇点,边数
        int u,v,z;//节点u,节点v,最大流量z
        char str[5];//处理空格
        int sp,sc;//超级源点,超级汇点
    
        while(~scanf("%d%d%d%d",&n,&np,&nc,&m)){
            memset(maze,0,sizeof(maze));
            for(int i=0;i<m;++i){
                scanf("%1s%d%1s%d%1s%d",str,&u,str,&v,str,&z);
                maze[u][v]=z;
            }
    
            //建立超级源点
            sp=n++;
            for(int i=0;i<np;++i){
                scanf("%1s%d%1s%d",str,&u,str,&z);
                maze[sp][u]=z;
            }
            //建立超级汇点
            sc=n++;
            for(int i=0;i<nc;++i){
                scanf("%1s%d%1s%d",str,&u,str,&z);
                maze[u][sc]=z;
            }
            printf("%d
    ",sap(sp,sc,n));
        }
        return 0;
    }
    View Code

    c3.ISAP邻接表形式:注意一下边数的范围

    /*
    ISAP邻接表形式
    */
    #include<iostream>
    #include<stdio.h>
    #include<string.h>
    using namespace std;
    
    const int MAXN=128;//点数的最大值
    const int MAXM=20500;//边数的最大值(加的双向加,所以是2倍,别忘了加上超级源点和超级汇点(共400条))
    const int INF=0x3f3f3f3f;
    struct Edge{
        int to,next,cap,flow;
    }edge[MAXM];//注意是MAXM
    int tol;
    int head[MAXN];
    int gap[MAXN],dep[MAXN],pre[MAXN],cur[MAXN];
    void init(){
        tol=0;
        memset(head,-1,sizeof(head));
    }
    //加边,单向图三个参数,双向图四个参数
    void addedge(int u,int v,int w,int rw=0){
        edge[tol].to=v;edge[tol].cap=w;edge[tol].next=head[u];
        edge[tol].flow=0;head[u]=tol++;
        edge[tol].to=u;edge[tol].cap=rw;edge[tol].next=head[v];
        edge[tol].flow=0;head[v]=tol++;
    }
    //输入参数:起点、终点、点的总数
    //点的编号没有影响,只要输入点的总数
    int sap(int start,int end,int N){
        memset(gap,0,sizeof(gap));
        memset(dep,0,sizeof(dep));
        memcpy(cur,head,sizeof(head));
        int u=start;
        pre[u]=-1;
        gap[0]=N;
        int ans=0;
        while(dep[start]<N){
            if(u==end){
                int Min=INF;
                for(int i=pre[u];i!=-1;i=pre[edge[i^1].to])
                    if(Min>edge[i].cap-edge[i].flow)
                        Min=edge[i].cap-edge[i].flow;
                for(int i=pre[u];i!=-1;i=pre[edge[i^1].to]){
                    edge[i].flow+=Min;
                    edge[i^1].flow-=Min;
                }
                u=start;
                ans+=Min;
                continue;
            }
            bool flag=false;
            int v;
            for(int i=cur[u];i!=-1;i=edge[i].next){
                v=edge[i].to;
                if(edge[i].cap-edge[i].flow&&dep[v]+1==dep[u]){
                    flag=true;
                    cur[u]=pre[v]=i;
                    break;
                }
            }
            if(flag){
                u=v;
                continue;
            }
            int Min=N;
            for(int i=head[u];i!=-1;i=edge[i].next)
                if(edge[i].cap-edge[i].flow&&dep[edge[i].to]<Min){
                    Min=dep[edge[i].to];
                    cur[u]=i;
                }
            gap[dep[u]]--;
            if(!gap[dep[u]])return ans;
            dep[u]=Min+1;
            gap[dep[u]]++;
            if(u!=start)u=edge[pre[u]^1].to;
        }
        return ans;
    }
    
    int main(){
        int n,np,nc,m;//节点总数,源点,汇点,边数
        int u,v,z;//节点u,节点v,最大流量z
        char str[5];//处理空格
        int sp,sc;//超级源点,超级汇点
    
        while(~scanf("%d%d%d%d",&n,&np,&nc,&m)){
            init();
            for(int i=0;i<m;++i){
                scanf("%1s%d%1s%d%1s%d",str,&u,str,&v,str,&z);
                addedge(u,v,z);
            }
    
            //建立超级源点
            sp=n++;
            for(int i=0;i<np;++i){
                scanf("%1s%d%1s%d",str,&u,str,&z);
                addedge(sp,u,z);
            }
            //建立超级汇点
            sc=n++;
            for(int i=0;i<nc;++i){
                scanf("%1s%d%1s%d",str,&u,str,&z);
                addedge(u,sc,z);
            }
            printf("%d
    ",sap(sp,sc,n));
        }
        return 0;
    }
    View Code

    c4.ISAP+bfs初始化+栈优化:注意一下边数的范围

    /*
    ISAP+bfs初始化+栈优化
    */
    #include<iostream>
    #include<stdio.h>
    #include<string.h>
    using namespace std;
    
    const int MAXN=128;//点数的最大值
    const int MAXM=20500;//边数的最大值
    const int INF=0x3f3f3f3f;
    struct Edge{
        int to,next,cap,flow;
    }edge[MAXM];//注意是MAXM
    int tol;
    int head[MAXN];
    int gap[MAXN],dep[MAXN],cur[MAXN];
    void init(){
        tol=0;
        memset(head,-1,sizeof(head));
    }
    void addedge(int u,int v,int w,int rw=0){
        edge[tol].to=v;edge[tol].cap=w;edge[tol].flow=0;
        edge[tol].next=head[u];head[u]=tol++;
        edge[tol].to=u;edge[tol].cap=rw;edge[tol].flow=0;
        edge[tol].next=head[v];head[v]=tol++;
    }
    int Q[MAXN];
    void BFS(int start,int end){
        memset(dep,-1,sizeof(dep));
        memset(gap,0,sizeof(gap));
        gap[0]=1;
        int front=0,rear=0;
        dep[end]=0;
        Q[rear++]=end;
        while(front!=rear){
            int u=Q[front++];
            for(int i=head[u];i!=-1;i=edge[i].next){
                int v=edge[i].to;
                if(dep[v]!=-1)continue;
                Q[rear++]=v;
                dep[v]=dep[u]+1;
                gap[dep[v]]++;
            }
        }
    }
    int S[MAXN];
    int sap(int start,int end,int N){
        BFS(start,end);
        memcpy(cur,head,sizeof(head));
        int top=0;
        int u=start;
        int ans=0;
        while(dep[start]<N){
            if(u==end){
                int Min=INF;
                int inser;
                for(int i=0;i<top;i++)
                    if(Min>edge[S[i]].cap-edge[S[i]].flow){
                        Min=edge[S[i]].cap-edge[S[i]].flow;
                        inser=i;
                    }
                for(int i=0;i<top;i++){
                    edge[S[i]].flow+=Min;
                    edge[S[i]^1].flow-=Min;
                }
                ans+=Min;
                top=inser;
                u=edge[S[top]^1].to;
                continue;
            }
            bool flag=false;
            int v;
            for(int i=cur[u];i!=-1;i=edge[i].next){
                v=edge[i].to;
                if(edge[i].cap-edge[i].flow&&dep[v]+1==dep[u]){
                    flag=true;
                    cur[u]=i;
                    break;
                }
            }
            if(flag){
                S[top++]=cur[u];
                u=v;
                continue;
            }
            int Min=N;
            for(int i=head[u];i!=-1;i=edge[i].next)
                if(edge[i].cap-edge[i].flow&&dep[edge[i].to]<Min){
                    Min=dep[edge[i].to];
                    cur[u]=i;
                }
            gap[dep[u]]--;
            if(!gap[dep[u]])return ans;
            dep[u]=Min+1;
            gap[dep[u]]++;
            if(u!=start)u=edge[S[--top]^1].to;
        }
        return ans;
    }
    
    int main(){
        int n,np,nc,m;//节点总数,源点,汇点,边数
        int u,v,z;//节点u,节点v,最大流量z
        char str[5];//处理空格
        int sp,sc;//超级源点,超级汇点
    
        while(~scanf("%d%d%d%d",&n,&np,&nc,&m)){
            init();
            for(int i=0;i<m;++i){
                scanf("%1s%d%1s%d%1s%d",str,&u,str,&v,str,&z);
                addedge(u,v,z);
            }
    
            //建立超级源点
            sp=n++;
            for(int i=0;i<np;++i){
                scanf("%1s%d%1s%d",str,&u,str,&z);
                addedge(sp,u,z);
            }
            //建立超级汇点
            sc=n++;
            for(int i=0;i<nc;++i){
                scanf("%1s%d%1s%d",str,&u,str,&z);
                addedge(u,sc,z);
            }
            printf("%d
    ",sap(sp,sc,n));
        }
        return 0;
    }
    View Code

    c5.dinic:注意一下边数的范围

    /*
    dinic
    */
    #include<iostream>
    #include<stdio.h>
    #include<string.h>
    using namespace std;
    
    const int MAXN=128;//点数的最大值
    const int MAXM=20500;//边数的最大值
    const int INF=0x3f3f3f3f;
    struct Edge{
        int to,next,cap,flow;
    }edge[MAXM];//注意是MAXM
    int tol;
    int head[MAXN];
    void init(){
        tol=2;
        memset(head,-1,sizeof(head));
    }
    void addedge(int u,int v,int w,int rw=0){
        edge[tol].to=v;edge[tol].cap=w;edge[tol].flow=0;
        edge[tol].next=head[u];head[u]=tol++;
        edge[tol].to=u;edge[tol].cap=rw;edge[tol].flow=0;
        edge[tol].next=head[v];head[v]=tol++;
    }
    int Q[MAXN];
    int dep[MAXN],cur[MAXN],sta[MAXN];
    bool bfs(int s,int t,int n){
        int front=0,tail=0;
        memset(dep,-1,sizeof(dep[0])*(n+1));
        dep[s]=0;
        Q[tail++]=s;
        while(front<tail){
            int u=Q[front++];
            for(int i=head[u];i!=-1;i=edge[i].next){
                int v=edge[i].to;
                if(edge[i].cap>edge[i].flow&&dep[v]==-1){
                    dep[v]=dep[u]+1;
                    if(v==t)return true;
                    Q[tail++]=v;
                }
            }
        }
        return false;
    }
    int dinic(int s,int t,int n){
        int maxflow=0;
        while(bfs(s,t,n)){
            for(int i=0;i<n;i++)cur[i]=head[i];
            int u=s,tail=0;
            while(cur[s]!=-1){
                if(u==t){
                    int tp=INF;
                    for(int i=tail-1;i>=0;i--)
                        tp=min(tp,edge[sta[i]].cap-edge[sta[i]].flow);
                    maxflow+=tp;
                    for(int i=tail-1;i>=0;i--){
                        edge[sta[i]].flow+=tp;
                        edge[sta[i]^1].flow-=tp;
                        if(edge[sta[i]].cap-edge[sta[i]].flow==0)
                            tail=i;
                    }
                    u=edge[sta[tail]^1].to;
                }
                else if(cur[u]!=-1&&edge[cur[u]].cap>edge[cur[u]].flow&&dep[u]+1==dep[edge[cur[u]].to]){
                    sta[tail++]=cur[u];
                    u=edge[cur[u]].to;
                }
                else{
                    while(u!=s&&cur[u]==-1)
                        u=edge[sta[--tail]^1].to;
                    cur[u]=edge[cur[u]].next;
                }
            }
        }
        return maxflow;
    }
    
    int main(){
        int n,np,nc,m;//节点总数,源点,汇点,边数
        int u,v,z;//节点u,节点v,最大流量z
        char str[5];//处理空格
        int sp,sc;//超级源点,超级汇点
    
        while(~scanf("%d%d%d%d",&n,&np,&nc,&m)){
            init();
            for(int i=0;i<m;++i){
                scanf("%1s%d%1s%d%1s%d",str,&u,str,&v,str,&z);
                addedge(u,v,z);
            }
    
            //建立超级源点
            sp=n++;
            for(int i=0;i<np;++i){
                scanf("%1s%d%1s%d",str,&u,str,&z);
                addedge(sp,u,z);
            }
            //建立超级汇点
            sc=n++;
            for(int i=0;i<nc;++i){
                scanf("%1s%d%1s%d",str,&u,str,&z);
                addedge(u,sc,z);
            }
            printf("%d
    ",dinic(sp,sc,n));
        }
        return 0;
    }
    View Code

    以上算法均取自kuangbin模板,ac时间均不到100ms。

    下面补上一个增广路算法(EdmondsKarp算法),但是时间让人捉急,1000多ms

    c6.增广路算法(EdmondsKarp算法):

    /*
    增广路算法(EdmondsKarp算法)
    */
    #include<iostream>
    #include<stdio.h>
    #include<vector>
    #include<string.h>
    #include<queue>
    using namespace std;
    
    const int maxn=128;
    const int INF=0x3f3f3f3f;
    
    struct Edge{
        int from,to,cap,flow;
        Edge(int u,int v,int c,int f):from(u),to(v),cap(c),flow(f){}
    };
    
    struct EdmondsKarp{
        int n,m;//n好像没用到
        vector<Edge>edges;//边数的两倍
        vector<int>G[maxn];//邻接表,G[i][j]表示结点i的第j条边在e数组中的序号
        int a[maxn];//当起点到i的可改进量
        int p[maxn];//最短路树上p的入弧编号
    
        void init(int n){
            for(int i=0;i<n;i++)G[i].clear();
            edges.clear();
        }
    
        void AddEdge(int from,int to,int cap){
            edges.push_back(Edge(from,to,cap,0));
            edges.push_back(Edge(to,from,0,0));//反向弧
            m=edges.size();
            G[from].push_back(m-2);
            G[to].push_back(m-1);
        }
    
        int Maxflow(int s,int t){
            int flow=0;
            for(;;){
                memset(a,0,sizeof(a));
                queue<int>Q;
                Q.push(s);
                a[s]=INF;
                while(!Q.empty()){
                    int x=Q.front();Q.pop();
                    for(int i=0;i<G[x].size();i++){
                        Edge &e=edges[G[x][i]];
                        if(!a[e.to]&&e.cap>e.flow){
                            p[e.to]=G[x][i];
                            a[e.to]=min(a[x],e.cap-e.flow);
                            Q.push(e.to);
                        }
                    }
                    if(a[t])break;
                }
                if(!a[t])break;
                for(int u=t;u!=s;u=edges[p[u]].from){
                    edges[p[u]].flow+=a[t];
                    edges[p[u]^1].flow-=a[t];
                }
                flow+=a[t];
            }
            return flow;
        }
    }EK;
    
    int main(){
        int n,np,nc,m;//节点总数,源点,汇点,边数
        int u,v,z;//节点u,节点v,最大流量z
        char str[5];//处理空格
        int sp,sc;//超级源点,超级汇点
    
        while(~scanf("%d%d%d%d",&n,&np,&nc,&m)){
            EK.init(n+2);//加上下面增加的超级源点和超级汇点
            for(int i=0;i<m;++i){
                scanf("%1s%d%1s%d%1s%d",str,&u,str,&v,str,&z);
                EK.AddEdge(u,v,z);
            }
    
            //建立超级源点
            sp=n++;
            for(int i=0;i<np;++i){
                scanf("%1s%d%1s%d",str,&u,str,&z);
                EK.AddEdge(sp,u,z);
            }
            //建立超级汇点
            sc=n++;
            for(int i=0;i<nc;++i){
                scanf("%1s%d%1s%d",str,&u,str,&z);
                EK.AddEdge(u,sc,z);
            }
            printf("%d
    ",EK.Maxflow(sp,sc));
        }
        return 0;
    }
    View Code

    2.最小费用最大流

    c.Bellman-Ford

    /*
    Bellman-Ford
    */
    #include<iostream>
    #include<stdio.h>
    #include<vector>
    #include<string.h>
    #include<queue>
    using namespace std;
    
    const int maxn=1024;
    const int INF=0x3f3f3f3f;
    
    struct Edge{
        int from,to,cap,flow,cost;
        Edge(int u,int v,int c,int f,int w):from(u),to(v),cap(c),flow(f),cost(w){}
    };
    
    struct MCMF{
        int n,m;
        vector<Edge>edges;
        vector<int>G[maxn];
        int inq[maxn];//是否在队列中
        int d[maxn];//Bellman-Ford
        int p[maxn];//上一条弧
        int a[maxn];//可改进量
    
        void init(int n){
            this->n=n;
            for(int i=0;i<n;i++)G[i].clear();
            edges.clear();
        }
    
        void AddEdge(int from,int to,int cap,int cost){
            edges.push_back(Edge(from,to,cap,0,cost));
            edges.push_back(Edge(to,from,0,0,-cost));
            m=edges.size();
            G[from].push_back(m-2);
            G[to].push_back(m-1);
        }
    
        bool BellmanFord(int s,int t,int &flow,long long &cost){
            for(int i=0;i<n;i++)d[i]=INF;
            memset(inq,0,sizeof(inq));
            d[s]=0;inq[s]=1;p[s]=0;a[s]=INF;
    
            queue<int>Q;
            Q.push(s);
            while(!Q.empty()){
                int u=Q.front();Q.pop();
                inq[u]=0;
                for(int i=0;i<G[u].size();i++){
                    Edge &e=edges[G[u][i]];
                    if(e.cap>e.flow&&d[e.to]>d[u]+e.cost){
                        d[e.to]=d[u]+e.cost;
                        p[e.to]=G[u][i];
                        a[e.to]=min(a[u],e.cap-e.flow);
                        if(!inq[e.to]){Q.push(e.to);inq[e.to]=1;}
                    }
                }
            }
            if(d[t]==INF)return false;
            flow+=a[t];
            cost+=(long long)d[t]*(long long)a[t];
            for(int u=t;u!=s;u=edges[p[u]].from){
                edges[p[u]].flow+=a[t];
                edges[p[u]^1].flow-=a[t];
            }
            return true;
        }
    
        //需要保证初始网络中没有负权圈
        int MincostMaxflow(int s,int t,long long &cost){
            int flow=0;cost=0;
            while(BellmanFord(s,t,flow,cost));
            return flow;
        }
    };
    
    int main(){
        return 0;
    }
    View Code

    c2.SPFA版费用流

    /*
    SPFA版费用流
    最小费用最大流,求最大费用最大流只需要取相反数,结果取相反数即可。
    点的总数为N,点的编号0~N-1
    */
    #include<iostream>
    #include<stdio.h>
    #include<string.h>
    #include<queue>
    using namespace std;
    
    const int MAXN=10000;
    const int MAXM=100000;
    const int INF=0x3f3f3f3f;
    struct Edge{
        int to,next,cap,flow,cost;
    }edge[MAXM];
    int head[MAXN],tol;
    int pre[MAXN],dis[MAXN];
    bool vis[MAXN];
    int N;//节点总个数,节点编号从0~N-1
    void init(int n){
        N=n;
        tol=0;
        memset(head,-1,sizeof(head));
    }
    void addedge(int u,int v,int cap,int cost){
        edge[tol].to=v;
        edge[tol].cap=cap;
        edge[tol].cost=cost;
        edge[tol].flow=0;
        edge[tol].next=head[u];
        head[u]=tol++;
        edge[tol].to=u;
        edge[tol].cap=0;
        edge[tol].cost=-cost;
        edge[tol].flow=0;
        edge[tol].next=head[v];
        head[v]=tol++;
    }
    bool spfa(int s,int t){
        queue<int>q;
        for(int i=0;i<N;i++){
            dis[i]=INF;
            vis[i]=false;
            pre[i]=-1;
        }
        dis[s]=0;
        vis[s]=true;
        q.push(s);
        while(!q.empty()){
            int u=q.front();
            q.pop();
            vis[u]=false;
            for(int i=head[u];i!=-1;i=edge[i].next){
                int v=edge[i].to;
                if(edge[i].cap>edge[i].flow&&dis[v]>dis[u]+edge[i].cost){
                    dis[v]=dis[u]+edge[i].cost;
                    pre[v]=i;
                    if(!vis[v]){
                        vis[v]=true;
                        q.push(v);
                    }
                }
            }
        }
        if(pre[t]==-1)return false;
        else return true;
    }
    //返回的是最大流,cost存的是最小费用
    int minCostMaxflow(int s,int t,int &cost){
        int flow=0;
        cost=0;
        while(spfa(s,t)){
            int Min=INF;
            for(int i=pre[t];i!=-1;i=pre[edge[i^1].to]){
                if(Min>edge[i].cap-edge[i].flow)
                    Min=edge[i].cap-edge[i].flow;
            }
            for(int i=pre[t];i!=-1;i=pre[edge[i^1].to]){
                edge[i].flow+=Min;
                edge[i^1].flow-=Min;
                cost+=edge[i].cost*Min;
            }
            flow+=Min;
        }
        return flow;
    }
    
    int main(){
        return 0;
    }
    View Code

    c3.zkw费用流

    /*
    zkw费用流
    对于二分图类型的比较高效
    */
    #include<iostream>
    #include<stdio.h>
    #include<string.h>
    using namespace std;
    
    const int MAXN=100;
    const int MAXM=20000;
    const int INF=0x3f3f3f3f;
    struct Edge{
        int to,next,cap,flow,cost;
        Edge(int _to=0,int _next=0,int _cap=0,int _flow=0,int _cost=0):
            to(_to),next(_next),cap(_cap),flow(_flow),cost(_cost){}
    }edge[MAXM];
    struct ZKW_MinCostMaxFlow{
        int head[MAXN],tot;
        int cur[MAXN];
        int dis[MAXN];
        bool vis[MAXN];
        int ss,tt,N;//源点、汇点和点的总个数(编号是0~N-1),不需要额外赋值,调用会直接赋值
        int min_cost,max_flow;
        void init(){
            tot=0;
            memset(head,-1,sizeof(head));
        }
        void addedge(int u,int v,int cap,int cost){
            edge[tot]=Edge(v,head[u],cap,0,cost);
            head[u]=tot++;
            edge[tot]=Edge(u,head[v],0,0,-cost);
            head[v]=tot++;
        }
        int aug(int u,int flow){
            if(u==tt)return flow;
            vis[u]=true;
            for(int i=cur[u];i!=-1;i=edge[i].next){
                int v=edge[i].to;
                if(edge[i].cap>edge[i].flow&&!vis[v]&&dis[u]==dis[v]+edge[i].cost){
                    int tmp=aug(v,min(flow,edge[i].cap-edge[i].flow));
                    edge[i].flow+=tmp;
                    edge[i^1].flow-=tmp;
                    cur[u]=i;
                    if(tmp)return tmp;
                }
            }
            return 0;
        }
        bool modify_label(){
            int d=INF;
            for(int u=0;u<N;u++)
                if(vis[u])
                    for(int i=head[u];i!=-1;i=edge[i].next){
                        int v=edge[i].to;
                        if(edge[i].cap>edge[i].flow&&!vis[v])
                            d=min(d,dis[v]+edge[i].cost-dis[u]);
                    }
            if(d==INF)return false;
            for(int i=0;i<N;i++)
                if(vis[i]){
                    vis[i]=false;
                    dis[i]+=d;
                }
            return true;
        }
        /*
        直接调用获取最小费用和最大流
        输入:start-源点,end-汇点,n-点的总个数(编号从0开始)
        返回值:pair<int,int>第一个是最小费用,第二个是最大流
        */
        pair<int,int> mincostmaxflow(int start,int end,int n){
            ss=start,tt=end,N=n;
            min_cost=max_flow=0;
            for(int i=0;i<n;i++)dis[i]=0;
            while(1){
                for(int i=0;i<n;i++)cur[i]=head[i];
                while(1){
                    for(int i=0;i<n;i++)vis[i]=false;
                    int tmp=aug(ss,INF);
                    if(tmp==0)break;
                    max_flow+=tmp;
                    min_cost+=tmp*dis[ss];
                }
                if(!modify_label())break;
            }
            return make_pair(min_cost,max_flow);
        }
    }solve;
    
    int main(){
        return 0;
    }
    View Code

    c4.这哥们的代码效率挺高,也挺清晰。可以参考。

    山东省第三届省赛 C 题 – An interesting game(费用流)

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  • 原文地址:https://www.cnblogs.com/gongpixin/p/5365242.html
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